What amount of FeSO4 should be added in 200g of water so that the resu...
Calculation of the amount of FeSO4 to be added in 200g of water to obtain a 10% solution
The problem requires us to find out the amount of FeSO4 to be added to obtain a 10% solution. This means that the final solution will contain 10% of FeSO4 by mass.
Determining the mass of FeSO4 in the final solution
Let us assume that x grams of FeSO4 are added to the water. Therefore, the mass of the final solution will be 200g + xg.
As per the problem statement, the final solution should contain 10% of FeSO4 by mass. Therefore,
Mass of FeSO4 in the final solution = 10% of (200g + xg)
Mass of FeSO4 in the final solution = 0.10(200g + xg)
Mass of FeSO4 in the final solution = 20g + 0.10xg
Equating the mass of FeSO4 in the final solution with the mass of FeSO4 added
We know that x grams of FeSO4 are added to the water. Therefore, the mass of FeSO4 added = xg.
Equating the mass of FeSO4 in the final solution with the mass of FeSO4 added, we get:
20g + 0.10xg = xg
Subtracting 0.10xg from both sides, we get:
20g = 0.90xg
Dividing both sides by 0.90g, we get:
x = 22.22g
Answer
Therefore, 22.22g of FeSO4 should be added to 200g of water to obtain a 10% solution of FeSO4 by mass.