Two men undertook to do a job for Rs. 1960. One of them can do it alon...
Let's assume that the amount of work done by the first man in one day is x and the amount of work done by the second man in one day is y.
- The first man can complete the job alone in 7 days, so in one day he completes 1/7th of the work, which can be represented as x = 1/7.
- Similarly, the second man can complete the job alone in 8 days, so in one day he completes 1/8th of the work, which can be represented as y = 1/8.
Combined work:
- When the two men work together, the total work done in one day is x + y.
- With the assistance of the boy, they complete the work in 3 days, which means they complete 1/3rd of the work in one day.
- So, we have the equation x + y + b = 1/3, where b represents the amount of work done by the boy in one day.
Finding the values of x, y, and b:
- We already know that x = 1/7 and y = 1/8.
- Substituting these values in the equation x + y + b = 1/3, we get 1/7 + 1/8 + b = 1/3.
- Finding a common denominator of 56, we get 8/56 + 7/56 + b = 18/56.
- Simplifying the equation, we have 15/56 + b = 18/56.
- Subtracting 15/56 from both sides, we get b = 3/56.
Calculating the boy's share of the money:
- Now that we know the amount of work done by the boy in one day is b = 3/56, we can calculate the boy's share of the money.
- The total amount of work is represented by 1, and the boy does 3/56th of the work.
- So, the boy's share of the money is (3/56) * 1960 = Rs. 105.
Therefore, the boy will receive Rs. 105, which is option C.