To calculate the equivalent capacitance of a network of capacitors, you need to determine how the capacitors are connected. In this case, c1 and c2 are in parallel, so the equivalent capacitance can be calculated using the following formula:

Ceq = C1 + C2

Substituting the values of c1 and c2, we get:

Ceq = 200pF + 100pF = 300pF

Therefore, the equivalent capacitance of the network is 300pF.



The energy stored in a capacitor is given by the following formula:

E = 1/2 CV^2

Where E is the energy stored, C is the capacitance, and V is the voltage across the capacitor.

To calculate the energy stored in the network, we need to know the voltage across each capacitor. Since the capacitors are in parallel, they have the same voltage across them.

Assuming that the voltage across the capacitors is V, we can calculate the energy stored in each capacitor using the formula:

E1 = 1/2 C1V^2

E2 = 1/2 C2V^2

Substituting the values of C1, C2, and V, we get:

E1 = 1/2 x 200pF x V^2 = 100V^2 pJ

E2 = 1/2 x 100pF x V^2 = 50V^2 pJ

The total energy stored in the network is the sum of the energy stored in each capacitor:

ETotal = E1 + E2

Substituting the values of E1 and E2, we get:

ETotal = 100V^2 pJ + 50V^2 pJ = 150V^2 pJ

Therefore, the energy stored in the network of capacitors is 150V^2 pJ.

Where is the "given network" ?