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For a highway in plane terrain, if ruling gradient is 1 in 20. the compensated gradient for a curve of radius
120 m is _______________ %
    Correct answer is between '4.30,4.45'. Can you explain this answer?
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    For a highway in plane terrain, if ruling gradient is 1 in 20. the com...
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    Calculation of Compensated Gradient for a Curve of Radius 120 m on a Highway:

    Given:
    Ruling Gradient = 1 in 20

    To find:
    Compensated Gradient for a Curve of Radius 120 m

    Formula:
    Compensated Gradient = Ruling Gradient + (Superelevation/Radius)
    Superelevation = (V^2)/(127*R)
    Where,
    V = Design Speed in km/hr
    R = Radius of Curve in meter

    Calculation:
    Assuming Design Speed = 80 km/hr

    Superelevation = (80^2)/(127*120)
    Superelevation = 0.42 m or 4.2%

    Compensated Gradient = 1/20 + (4.2/120)
    Compensated Gradient = 0.0525 + 0.035
    Compensated Gradient = 0.0875 or 8.75%

    Therefore, the Compensated Gradient for a Curve of Radius 120 m on a Highway is 8.75%.

    Explanation:

    - The ruling gradient is the maximum allowed gradient on a highway that can be used for a long distance without causing any discomfort to the passengers.
    - The compensated gradient is the gradient that takes into account the effect of super-elevation on a curved road section.
    - The super-elevation is the banking of a road at a curve to counter the centrifugal force acting on the vehicles.
    - The formula for calculating the compensated gradient takes into account the ruling gradient and the super-elevation.
    - The radius of the curve also affects the super-elevation, and hence, the compensated gradient.
    - In this case, assuming a design speed of 80 km/hr, the super-elevation is calculated to be 4.2%.
    - Substituting the values in the formula for compensated gradient gives a value of 8.75%.
    - Therefore, for a highway with a ruling gradient of 1 in 20 and a curve of radius 120 m, the compensated gradient is 8.75%.
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    For a highway in plane terrain, if ruling gradient is 1 in 20. the compensated gradient for a curve of radius120 m is _______________ %Correct answer is between '4.30,4.45'. Can you explain this answer?
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