In the figure shown below, ABC is a triangle with A = 45. P and Q are the points on the sides AB and AC respectively such that PQ is parallel to BC. Also, the diagonals of the trapezium PQCB i.e. BQ and PC intersect at right angles. If PQ = 6 cm and BC = 14 cm, find the area (in cm2) of the trapezoid PQCB. a)84b)102c)105d)98e)91Correct answer is option 'C'. Can you explain this answer?

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In the figure shown below, ABC is a triangle with

A = 45°. P and Q are the points on the sides AB and AC respectively such that PQ is parallel to BC. Also, the diagonals of the trapezium PQCB i.e. BQ and PC intersect at right angles. If PQ = 6 cm and BC = 14 cm, find the area (in cm²) of the trapezoid PQCB.

a)
84
b)
102
c)
105
d)
98
e)
91

Correct answer is option 'C'. Can you explain this answer?

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In the figure shown below, ABC is a triangle with A = 45°. P and ...

We have

M = 90°.
Area of the trapezium PQBC = Area of ΔPBQ + Area of ΔCBQ

(Since

A = 45° is given)

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In the figure shown below, ABC is a triangle with A = 45°. P and Q are the points on the sides AB and AC respectively such that PQ is parallel to BC. Also, the diagonals of the trapezium PQCB i.e. BQ and PC intersect at right angles. If PQ = 6 cm and BC = 14 cm, find the area (in cm2) of the trapezoid PQCB. a)84b)102c)105d)98e)91Correct answer is option 'C'. Can you explain this answer?

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