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Reaction of one molecule of HBr with one molecule of 1 , 3-butadiene at 40°C gives predominantly
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- a)1-bromo-2-butene under kinetically controlled conditions
- b)3-bromobutene under thermodynamically controlled conditions
- c)1 -bromo-2-butene under thermodynamically controlled conditions
- d)3-bromobutene under kinetically controlled conditions
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Reaction of one molecule of HBr with one molecule of 1 , 3-butadiene a...
Addition is through the formation of allylic carbocation.
Under mild conditions (temperature = - 80°C) kinetic product is the 1, 2-addition product and under vigorous conditions, (temp. = 4°C) thermodynamic product is the 1 , 4-addition product.
Thus, 1-bromo-2-butene is the major product under given condition.
Most Upvoted Answer
Reaction of one molecule of HBr with one molecule of 1 , 3-butadiene a...
The reaction between one molecule of HBr (hydrogen bromide) and one molecule of 1,3-butadiene at 40°C can result in the formation of different products depending on the reaction conditions.
Under kinetically controlled conditions, the reaction proceeds through the formation of a carbocation intermediate. In this case, the reaction is fast and reversible, and the product is predominantly determined by the stability of the carbocation intermediate.
Under thermodynamically controlled conditions, the reaction proceeds through the formation of a more stable product, which is determined by the stability of the final product.
In the given question, the reaction is conducted at 40°C, which is a relatively low temperature. At this temperature, the reaction is expected to be kinetically controlled rather than thermodynamically controlled.
Now let's analyze the possible products of the reaction:
1. 1-Bromo-2-butene: The addition of HBr to 1,3-butadiene can result in the formation of 1-bromo-2-butene. This product is formed by adding the bromine atom to the second carbon of the butadiene molecule. This product is more stable than 3-bromobutene due to the presence of a double bond.
2. 3-Bromobutene: The addition of HBr to 1,3-butadiene can also result in the formation of 3-bromobutene. This product is formed by adding the bromine atom to the third carbon of the butadiene molecule. This product is less stable than 1-bromo-2-butene due to the presence of a double bond.
Based on the given information, the reaction is predominantly expected to give 1-bromo-2-butene under thermodynamically controlled conditions. This is because under thermodynamic conditions, the more stable product is favored, and 1-bromo-2-butene is more stable than 3-bromobutene due to the presence of a double bond.
Therefore, the correct answer is option 'C': 1-bromo-2-butene under thermodynamically controlled conditions.
Under kinetically controlled conditions, the reaction proceeds through the formation of a carbocation intermediate. In this case, the reaction is fast and reversible, and the product is predominantly determined by the stability of the carbocation intermediate.
Under thermodynamically controlled conditions, the reaction proceeds through the formation of a more stable product, which is determined by the stability of the final product.
In the given question, the reaction is conducted at 40°C, which is a relatively low temperature. At this temperature, the reaction is expected to be kinetically controlled rather than thermodynamically controlled.
Now let's analyze the possible products of the reaction:
1. 1-Bromo-2-butene: The addition of HBr to 1,3-butadiene can result in the formation of 1-bromo-2-butene. This product is formed by adding the bromine atom to the second carbon of the butadiene molecule. This product is more stable than 3-bromobutene due to the presence of a double bond.
2. 3-Bromobutene: The addition of HBr to 1,3-butadiene can also result in the formation of 3-bromobutene. This product is formed by adding the bromine atom to the third carbon of the butadiene molecule. This product is less stable than 1-bromo-2-butene due to the presence of a double bond.
Based on the given information, the reaction is predominantly expected to give 1-bromo-2-butene under thermodynamically controlled conditions. This is because under thermodynamic conditions, the more stable product is favored, and 1-bromo-2-butene is more stable than 3-bromobutene due to the presence of a double bond.
Therefore, the correct answer is option 'C': 1-bromo-2-butene under thermodynamically controlled conditions.
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Reaction of one molecule of HBr with one molecule of 1 , 3-butadiene at 40°C gives predominantly(AIEEE2005)a)1-bromo-2-butene under kinetically controlled conditionsb)3-bromobutene under thermodynamically controlled conditionsc)1 -bromo-2-butene under thermodynamically controlled conditionsd)3-bromobutene under kinetically controlled conditionsCorrect answer is option 'C'. Can you explain this answer?
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Reaction of one molecule of HBr with one molecule of 1 , 3-butadiene at 40°C gives predominantly(AIEEE2005)a)1-bromo-2-butene under kinetically controlled conditionsb)3-bromobutene under thermodynamically controlled conditionsc)1 -bromo-2-butene under thermodynamically controlled conditionsd)3-bromobutene under kinetically controlled conditionsCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Reaction of one molecule of HBr with one molecule of 1 , 3-butadiene at 40°C gives predominantly(AIEEE2005)a)1-bromo-2-butene under kinetically controlled conditionsb)3-bromobutene under thermodynamically controlled conditionsc)1 -bromo-2-butene under thermodynamically controlled conditionsd)3-bromobutene under kinetically controlled conditionsCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Reaction of one molecule of HBr with one molecule of 1 , 3-butadiene at 40°C gives predominantly(AIEEE2005)a)1-bromo-2-butene under kinetically controlled conditionsb)3-bromobutene under thermodynamically controlled conditionsc)1 -bromo-2-butene under thermodynamically controlled conditionsd)3-bromobutene under kinetically controlled conditionsCorrect answer is option 'C'. Can you explain this answer?.
Reaction of one molecule of HBr with one molecule of 1 , 3-butadiene at 40°C gives predominantly(AIEEE2005)a)1-bromo-2-butene under kinetically controlled conditionsb)3-bromobutene under thermodynamically controlled conditionsc)1 -bromo-2-butene under thermodynamically controlled conditionsd)3-bromobutene under kinetically controlled conditionsCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Reaction of one molecule of HBr with one molecule of 1 , 3-butadiene at 40°C gives predominantly(AIEEE2005)a)1-bromo-2-butene under kinetically controlled conditionsb)3-bromobutene under thermodynamically controlled conditionsc)1 -bromo-2-butene under thermodynamically controlled conditionsd)3-bromobutene under kinetically controlled conditionsCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Reaction of one molecule of HBr with one molecule of 1 , 3-butadiene at 40°C gives predominantly(AIEEE2005)a)1-bromo-2-butene under kinetically controlled conditionsb)3-bromobutene under thermodynamically controlled conditionsc)1 -bromo-2-butene under thermodynamically controlled conditionsd)3-bromobutene under kinetically controlled conditionsCorrect answer is option 'C'. Can you explain this answer?.
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