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Nickel (Z = 28) combines with a uninegative monodentate ligand X– to form a paramagnetic complex [NiX4]2–. The number of unpaired electron(s) in the nickel and geometry of this complex ion are, respectively :
  • a)
    one, square planar
  • b)
    two, square planar
  • c)
    one, tetrahedral
  • d)
    two, tetrahedral
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Nickel (Z = 28) combines with a uninegative monodentate ligand X&ndash...
[NiX4]2–, the electronic configuration of Ni2+ is
It contains two unpaired electrons and the hybridisation is sp3 (tetrahedral).
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Nickel (Z = 28) combines with a uninegative monodentate ligand X– to form a paramagnetic complex [NiX4]2–. The number of unpaired electron(s) in the nickel and geometry of this complex ion are, respectively :a)one, square planarb)two, square planarc)one, tetrahedrald)two, tetrahedralCorrect answer is option 'D'. Can you explain this answer?
Question Description
Nickel (Z = 28) combines with a uninegative monodentate ligand X– to form a paramagnetic complex [NiX4]2–. The number of unpaired electron(s) in the nickel and geometry of this complex ion are, respectively :a)one, square planarb)two, square planarc)one, tetrahedrald)two, tetrahedralCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Nickel (Z = 28) combines with a uninegative monodentate ligand X– to form a paramagnetic complex [NiX4]2–. The number of unpaired electron(s) in the nickel and geometry of this complex ion are, respectively :a)one, square planarb)two, square planarc)one, tetrahedrald)two, tetrahedralCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Nickel (Z = 28) combines with a uninegative monodentate ligand X– to form a paramagnetic complex [NiX4]2–. The number of unpaired electron(s) in the nickel and geometry of this complex ion are, respectively :a)one, square planarb)two, square planarc)one, tetrahedrald)two, tetrahedralCorrect answer is option 'D'. Can you explain this answer?.
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