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In the arrangement shown in fig the block of mass m=2 kg lies on wedge on mass M=8 kg Find the initial acceleration of wedge if the surface are smooth and pulley and string are massless.?
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In the arrangement shown in fig the block of mass m=2 kg lies on wedge...
Problem: A block of mass m=2 kg lies on a wedge of mass M=8 kg. Find the initial acceleration of the wedge if the surfaces are smooth and the pulley and string are massless.

Solution:

Step 1: Draw a Free Body Diagram of the block and the wedge

Step 2: Write down the equations of motion for the block and the wedge using Newton's Second Law

For the block:
m*a = T - m*g*sin(theta)
For the wedge:
M*A = m*g*cos(theta)

Step 3: Find the tension in the string

T = m*g*sin(theta)/(1 + M/m)

Step 4: Substitute the tension into the equation for the acceleration of the wedge

A = m*g*cos(theta)/(M + m*sin^2(theta))

Step 5: Substitute the given values of m, M, and theta into the equation for the acceleration of the wedge

A = (2*9.8*cos(30))/(8 + 2*sin^2(30))

Step 6: Solve for the acceleration of the wedge

A = 0.98 m/s^2

Therefore, the initial acceleration of the wedge is 0.98 m/s^2.
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In the arrangement shown in fig the block of mass m=2 kg lies on wedge...
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