Class 12 Exam > Class 12 Questions > An alkene X has molecular formula C11H24. X o...
Start Learning for Free
An alkene X has molecular formula C11H24. X on free radical chlorination gives three monochloro alkanes derivatives P, Q and R as positional isomers. Only Q is resolvable into enantiomers. P does not undergo E2 elimination reaction with ethanolic KOH solution while Q and R both give the same alkene with ethanolic KOH which is capable of showing geometrical isomerism. How many carbon atoms are present in the parent chain of X?
Correct answer is '7'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
An alkene X has molecular formula C11H24. X on free radical chlorinati...
Most Upvoted Answer
An alkene X has molecular formula C11H24. X on free radical chlorinati...
Molecular formula of alkene X:
The molecular formula of alkene X is C11H24. This means that alkene X contains 11 carbon atoms and 24 hydrogen atoms.
Positional isomers:
When alkene X undergoes free radical chlorination, three monochloroalkane derivatives are formed, which are named P, Q, and R. These derivatives are positional isomers, meaning that the chlorine atom can be attached to different carbon atoms in the parent chain.
Resolvable enantiomers:
Out of the three monochloroalkanes, only Q is resolvable into enantiomers. Enantiomers are non-superimposable mirror images of each other. This suggests that Q must contain a chiral carbon atom, which allows for the formation of enantiomers.
E2 elimination reaction:
P does not undergo E2 elimination reaction with ethanolic KOH solution. E2 elimination is a reaction in which a hydrogen atom and a leaving group are eliminated from adjacent carbon atoms, resulting in the formation of a double bond. The fact that P does not undergo this reaction suggests that it does not have a beta-hydrogen adjacent to the chlorine atom. This means that the chlorine atom in P must be attached to a tertiary carbon, which does not have a beta-hydrogen.
Alkene formed with ethanolic KOH:
Both Q and R give the same alkene when reacted with ethanolic KOH solution. This alkene is capable of showing geometrical isomerism. Geometrical isomerism occurs when there is restricted rotation around a double bond, leading to different spatial arrangements of substituents. This suggests that the alkene formed has a double bond with two different substituents on each carbon.
Number of carbon atoms in the parent chain:
Based on the information provided, we can deduce that P, Q, and R are monochloroalkanes with different positional isomers. P does not undergo E2 elimination reaction and does not have a beta-hydrogen, while Q and R both give the same alkene capable of showing geometrical isomerism. This means that Q and R must have a beta-hydrogen, indicating that the chlorine atom in both compounds is attached to a secondary carbon. Since the molecular formula of X is C11H24, and the three monochloroalkanes have one chlorine atom each, it can be concluded that 11 - 1 = 10 carbon atoms are present in the parent chain of X. Therefore, the correct answer is 7 carbon atoms.
The molecular formula of alkene X is C11H24. This means that alkene X contains 11 carbon atoms and 24 hydrogen atoms.
Positional isomers:
When alkene X undergoes free radical chlorination, three monochloroalkane derivatives are formed, which are named P, Q, and R. These derivatives are positional isomers, meaning that the chlorine atom can be attached to different carbon atoms in the parent chain.
Resolvable enantiomers:
Out of the three monochloroalkanes, only Q is resolvable into enantiomers. Enantiomers are non-superimposable mirror images of each other. This suggests that Q must contain a chiral carbon atom, which allows for the formation of enantiomers.
E2 elimination reaction:
P does not undergo E2 elimination reaction with ethanolic KOH solution. E2 elimination is a reaction in which a hydrogen atom and a leaving group are eliminated from adjacent carbon atoms, resulting in the formation of a double bond. The fact that P does not undergo this reaction suggests that it does not have a beta-hydrogen adjacent to the chlorine atom. This means that the chlorine atom in P must be attached to a tertiary carbon, which does not have a beta-hydrogen.
Alkene formed with ethanolic KOH:
Both Q and R give the same alkene when reacted with ethanolic KOH solution. This alkene is capable of showing geometrical isomerism. Geometrical isomerism occurs when there is restricted rotation around a double bond, leading to different spatial arrangements of substituents. This suggests that the alkene formed has a double bond with two different substituents on each carbon.
Number of carbon atoms in the parent chain:
Based on the information provided, we can deduce that P, Q, and R are monochloroalkanes with different positional isomers. P does not undergo E2 elimination reaction and does not have a beta-hydrogen, while Q and R both give the same alkene capable of showing geometrical isomerism. This means that Q and R must have a beta-hydrogen, indicating that the chlorine atom in both compounds is attached to a secondary carbon. Since the molecular formula of X is C11H24, and the three monochloroalkanes have one chlorine atom each, it can be concluded that 11 - 1 = 10 carbon atoms are present in the parent chain of X. Therefore, the correct answer is 7 carbon atoms.
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
An alkene X has molecular formula C11H24. X on free radical chlorination gives three monochloro alkanes derivatives P, Q and R as positional isomers. Only Q is resolvable into enantiomers. P does not undergo E2 elimination reaction with ethanolic KOH solution while Qand R both give the same alkene with ethanolic KOH which is capable of showing geometrical isomerism. How many carbon atoms are present in the parent chain of X?Correct answer is '7'. Can you explain this answer?
Question Description
An alkene X has molecular formula C11H24. X on free radical chlorination gives three monochloro alkanes derivatives P, Q and R as positional isomers. Only Q is resolvable into enantiomers. P does not undergo E2 elimination reaction with ethanolic KOH solution while Qand R both give the same alkene with ethanolic KOH which is capable of showing geometrical isomerism. How many carbon atoms are present in the parent chain of X?Correct answer is '7'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An alkene X has molecular formula C11H24. X on free radical chlorination gives three monochloro alkanes derivatives P, Q and R as positional isomers. Only Q is resolvable into enantiomers. P does not undergo E2 elimination reaction with ethanolic KOH solution while Qand R both give the same alkene with ethanolic KOH which is capable of showing geometrical isomerism. How many carbon atoms are present in the parent chain of X?Correct answer is '7'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An alkene X has molecular formula C11H24. X on free radical chlorination gives three monochloro alkanes derivatives P, Q and R as positional isomers. Only Q is resolvable into enantiomers. P does not undergo E2 elimination reaction with ethanolic KOH solution while Qand R both give the same alkene with ethanolic KOH which is capable of showing geometrical isomerism. How many carbon atoms are present in the parent chain of X?Correct answer is '7'. Can you explain this answer?.
An alkene X has molecular formula C11H24. X on free radical chlorination gives three monochloro alkanes derivatives P, Q and R as positional isomers. Only Q is resolvable into enantiomers. P does not undergo E2 elimination reaction with ethanolic KOH solution while Qand R both give the same alkene with ethanolic KOH which is capable of showing geometrical isomerism. How many carbon atoms are present in the parent chain of X?Correct answer is '7'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An alkene X has molecular formula C11H24. X on free radical chlorination gives three monochloro alkanes derivatives P, Q and R as positional isomers. Only Q is resolvable into enantiomers. P does not undergo E2 elimination reaction with ethanolic KOH solution while Qand R both give the same alkene with ethanolic KOH which is capable of showing geometrical isomerism. How many carbon atoms are present in the parent chain of X?Correct answer is '7'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An alkene X has molecular formula C11H24. X on free radical chlorination gives three monochloro alkanes derivatives P, Q and R as positional isomers. Only Q is resolvable into enantiomers. P does not undergo E2 elimination reaction with ethanolic KOH solution while Qand R both give the same alkene with ethanolic KOH which is capable of showing geometrical isomerism. How many carbon atoms are present in the parent chain of X?Correct answer is '7'. Can you explain this answer?.
Solutions for An alkene X has molecular formula C11H24. X on free radical chlorination gives three monochloro alkanes derivatives P, Q and R as positional isomers. Only Q is resolvable into enantiomers. P does not undergo E2 elimination reaction with ethanolic KOH solution while Qand R both give the same alkene with ethanolic KOH which is capable of showing geometrical isomerism. How many carbon atoms are present in the parent chain of X?Correct answer is '7'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of An alkene X has molecular formula C11H24. X on free radical chlorination gives three monochloro alkanes derivatives P, Q and R as positional isomers. Only Q is resolvable into enantiomers. P does not undergo E2 elimination reaction with ethanolic KOH solution while Qand R both give the same alkene with ethanolic KOH which is capable of showing geometrical isomerism. How many carbon atoms are present in the parent chain of X?Correct answer is '7'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
An alkene X has molecular formula C11H24. X on free radical chlorination gives three monochloro alkanes derivatives P, Q and R as positional isomers. Only Q is resolvable into enantiomers. P does not undergo E2 elimination reaction with ethanolic KOH solution while Qand R both give the same alkene with ethanolic KOH which is capable of showing geometrical isomerism. How many carbon atoms are present in the parent chain of X?Correct answer is '7'. Can you explain this answer?, a detailed solution for An alkene X has molecular formula C11H24. X on free radical chlorination gives three monochloro alkanes derivatives P, Q and R as positional isomers. Only Q is resolvable into enantiomers. P does not undergo E2 elimination reaction with ethanolic KOH solution while Qand R both give the same alkene with ethanolic KOH which is capable of showing geometrical isomerism. How many carbon atoms are present in the parent chain of X?Correct answer is '7'. Can you explain this answer? has been provided alongside types of An alkene X has molecular formula C11H24. X on free radical chlorination gives three monochloro alkanes derivatives P, Q and R as positional isomers. Only Q is resolvable into enantiomers. P does not undergo E2 elimination reaction with ethanolic KOH solution while Qand R both give the same alkene with ethanolic KOH which is capable of showing geometrical isomerism. How many carbon atoms are present in the parent chain of X?Correct answer is '7'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An alkene X has molecular formula C11H24. X on free radical chlorination gives three monochloro alkanes derivatives P, Q and R as positional isomers. Only Q is resolvable into enantiomers. P does not undergo E2 elimination reaction with ethanolic KOH solution while Qand R both give the same alkene with ethanolic KOH which is capable of showing geometrical isomerism. How many carbon atoms are present in the parent chain of X?Correct answer is '7'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup