Sashi can do a piece of work in 25 days and Rishi can do it in 20 days...
Sashi = 4%, Rishi = 5%. In five days, they do a total of 45% work. Rishi will finish the remaining
55% work in 11 more days.
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Sashi can do a piece of work in 25 days and Rishi can do it in 20 days...
Given:
Sashi can do the work in 25 days
Rishi can do the work in 20 days
They worked together for 5 days
To find:
In how many more days will Rishi finish the work?
Solution:
Let's assume that the total work is 100 units.
So, Sashi can do 4 units of work in a day, and Rishi can do 5 units of work in a day.
In the first 5 days, the total work done by Sashi and Rishi together is:
Sashi's work = 4 units/day * 5 days = 20 units
Rishi's work = 5 units/day * 5 days = 25 units
Total work done = 20+25 = 45 units
Remaining work = 100 - 45 = 55 units
Now, only Rishi is working on the remaining work. So, the time taken by Rishi to complete the remaining work will be:
Time = Remaining work / Rishi's efficiency
Time = 55 units / 5 units/day = 11 days
Therefore, the total time taken by Rishi to complete the work is:
Time taken = 5 days (when Sashi and Rishi worked together) + 11 days (when only Rishi worked)
= 16 days
Hence, the correct answer is option D, none of these.
Sashi can do a piece of work in 25 days and Rishi can do it in 20 days...
Sashi one day work 1/25 and Rishi one day work is 1/20. they work together for 5 day (1/25+1/20)×5 =9/20. remaining work will be (1-9/20)= 11/20. Rishi will do the remaining work.11/20÷1/20 =11day