Passage IIIn an E2 reaction, following one step mechanism is involved.As shown in the above mechanism, aandbeta;-proton anti to leaving group is abstracted by the alkoxide base. If a less bulky base is used, andbeta;-proton is eliminated giving most substituted, most stable product as the major product. On the otherhand if a bulky base is used, andbeta;-proton is abstracted from andbeta;-carbon where there is least steric hindrance and this gives least substituted, although least stable, alkene as the major product.Q.In the following reaction, how many elimination products would be formed in principle by E2 mechanism?a)2b)3c)4d)5Correct answer is option 'D'. Can you explain this answer?

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Passage II

In an E2 reaction, following one step mechanism is involved.

As shown in the above mechanism, a β-proton anti to leaving group is abstracted by the alkoxide base. If a less bulky base is used, β-proton is eliminated giving most substituted, most stable product as the major product. On the otherhand if a bulky base is used, β-proton is abstracted from β-carbon where there is least steric hindrance and this gives least substituted, although least stable, alkene as the major product.

In the following reaction, how many elimination products would be formed in principle by E2 mechanism?

a)
2
b)
3
c)
4
d)
5

Correct answer is option 'D'. Can you explain this answer?

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Passage IIIn an E2 reaction, following one step mechanism is involved.As shown in the above mechanism, aβ-proton anti to leaving group is abstracted by the alkoxide base. If a less bulky base is used, β-proton is eliminated giving most substituted, most stable product as the major product. On the otherhand if a bulky base is used, β-proton is abstracted from β-carbon where there is least steric hindrance and this gives least substituted, although least stable, alkene as the major product.Q.What is the major product in the following elimination reaction?

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Passage IIIn an E2 reaction, following one step mechanism is involved.As shown in the above mechanism, aβ-proton anti to leaving group is abstracted by the alkoxide base. If a less bulky base is used, β-proton is eliminated giving most substituted, most stable product as the major product. On the otherhand if a bulky base is used, β-proton is abstracted from β-carbon where there is least steric hindrance and this gives least substituted, although least stable, alkene as the major product.Q.What is the major elimination product in the following reaction?

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Consider the following elimination reaction,When reaction is carried out with C2H5ONain ethanol, 2-menthene is the major product while 3-menthene is the major product if reaction is substrate is heated in ethanol only. It is due to

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Read the passage given below and answer the following questions:Nucleophilic substitution reaction of haloalkane can be conducted according to both SN1 and SN2 mechanisms. However, which mechanism it is based on is related to such factors as the structure of haloalkane, and properties of leaving group, nucleophilic reagent and solvent. Influences of halogen: No matter which mechanism the nucleophilic substitution reaction is based on, the leaving group always leave the central carbon atom with electron pair. This is just the opposite of the situation that nucleophilic reagent attacks the central carbon atom with electron pair. Therefore, the weaker the alkalinity of leaving group is , the more stable the anion formed is and it will be more easier for the leaving group to leave the central carbon atom; that is to say, the reactant is more easier to be substituted. The alkalinity order of halogen ion is I− < Br− < Cl− < F− and the order of their leaving tendency should be I− > Br− > Cl− > F−. Therefore, in four halides with the same alkyl and different halogens, the order of substitution reaction rate is RI > RBr > RCl > RF. In addition, if the leaving group is very easy to leave, many carbocation intermediates are generated in the reaction and the reaction is based on SN1 mechanism. If the leaving group is not easy to leave, the reaction is based on SN2 mechanism. Influences of solvent polarity: In SN1 reaction, the polarity of the system increases from the reactant to the transition state, because polar solvent has a greater stabilizing effect on the transition state than the reactant, thereby reduce activation energy and accelerate the reaction. In SN2 reaction, the polarity of the system generally does not change from the reactant to the transition state and only charge dispersion occurs. At this time, polar solvent has a great stabilizing effect on Nu than the transition state, thereby increasing activation energy and slow down the reaction rate. For example, the decomposition rate (SN1) of tertiary chlorobutane in 25° water (dielectric constant 79) is 300000 times faster than in ethanol (dielectric constant 24). The reaction rate (SN2) of 2-bromopropane and NaOH in ethanol containing 40% water is twice slower than in absolute ethanol. In a word, the level of solvent polarity has influence on both SN1 and SN2 reactions, but with different results. Generally speaking, weak polar solvent is favorable for SN2 reaction, while strong polar solvent is favorable for SN1 reaction, because only under the action of polar solvent can halogenated hydrocarbon dissociate into carbocation and halogen ion and solvents with a strong polarity is favorable for solvation of carbocation, increasing its stability. Generally speaking, the substitution reaction of tertiary haloalkane is based on SN1 mechanism in solvents with a strong polarity (for example, ethanol containing water).Q. Polar solvents make the reaction faster as they

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Passage IIWhen compound 1 is heated with C2H5ONa compound 2 and 3 are formed:Two mechanisms were proposed for reaction I.Mechanism A HBr is eliminated from compound 1 to form a symmetrical vinyl carbene intermediate A, which then rearranges to compound 2.Mechanism B Ethoxide ion first abstract a proton to form a carbanion intermediate B which then rearranges with loss of bromide ion to form compound 2To distinguish between the two machanisms, an isotopic labeling experiment was designed. Two compounds (Compound 4 and 5) were labelled with C-14 and each was treated separately with sodium ethoxide under identical experimental condition where following results were obtained.Q.In reaction scheme 1, had the α-C to bromine be labelled with C-14

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Passage IIIn an E2 reaction, following one step mechanism is involved.As shown in the above mechanism, aβ-proton anti to leaving group is abstracted by the alkoxide base. If a less bulky base is used, β-proton is eliminated giving most substituted, most stable product as the major product. On the otherhand if a bulky base is used, β-proton is abstracted from β-carbon where there is least steric hindrance and this gives least substituted, although least stable, alkene as the major product.Q.In the following reaction, how many elimination products would be formed in principle by E2 mechanism?a)2b)3c)4d)5Correct answer is option 'D'. Can you explain this answer?

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Passage IIIn an E2 reaction, following one step mechanism is involved.As shown in the above mechanism, aβ-proton anti to leaving group is abstracted by the alkoxide base. If a less bulky base is used, β-proton is eliminated giving most substituted, most stable product as the major product. On the otherhand if a bulky base is used, β-proton is abstracted from β-carbon where there is least steric hindrance and this gives least substituted, although least stable, alkene as the major product.Q.In the following reaction, how many elimination products would be formed in principle by E2 mechanism?a)2b)3c)4d)5Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Passage IIIn an E2 reaction, following one step mechanism is involved.As shown in the above mechanism, aβ-proton anti to leaving group is abstracted by the alkoxide base. If a less bulky base is used, β-proton is eliminated giving most substituted, most stable product as the major product. On the otherhand if a bulky base is used, β-proton is abstracted from β-carbon where there is least steric hindrance and this gives least substituted, although least stable, alkene as the major product.Q.In the following reaction, how many elimination products would be formed in principle by E2 mechanism?a)2b)3c)4d)5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Passage IIIn an E2 reaction, following one step mechanism is involved.As shown in the above mechanism, aβ-proton anti to leaving group is abstracted by the alkoxide base. If a less bulky base is used, β-proton is eliminated giving most substituted, most stable product as the major product. On the otherhand if a bulky base is used, β-proton is abstracted from β-carbon where there is least steric hindrance and this gives least substituted, although least stable, alkene as the major product.Q.In the following reaction, how many elimination products would be formed in principle by E2 mechanism?a)2b)3c)4d)5Correct answer is option 'D'. Can you explain this answer?.

Solutions for Passage IIIn an E2 reaction, following one step mechanism is involved.As shown in the above mechanism, aβ-proton anti to leaving group is abstracted by the alkoxide base. If a less bulky base is used, β-proton is eliminated giving most substituted, most stable product as the major product. On the otherhand if a bulky base is used, β-proton is abstracted from β-carbon where there is least steric hindrance and this gives least substituted, although least stable, alkene as the major product.Q.In the following reaction, how many elimination products would be formed in principle by E2 mechanism?a)2b)3c)4d)5Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.

Here you can find the meaning of Passage IIIn an E2 reaction, following one step mechanism is involved.As shown in the above mechanism, aβ-proton anti to leaving group is abstracted by the alkoxide base. If a less bulky base is used, β-proton is eliminated giving most substituted, most stable product as the major product. On the otherhand if a bulky base is used, β-proton is abstracted from β-carbon where there is least steric hindrance and this gives least substituted, although least stable, alkene as the major product.Q.In the following reaction, how many elimination products would be formed in principle by E2 mechanism?a)2b)3c)4d)5Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Passage IIIn an E2 reaction, following one step mechanism is involved.As shown in the above mechanism, aβ-proton anti to leaving group is abstracted by the alkoxide base. If a less bulky base is used, β-proton is eliminated giving most substituted, most stable product as the major product. On the otherhand if a bulky base is used, β-proton is abstracted from β-carbon where there is least steric hindrance and this gives least substituted, although least stable, alkene as the major product.Q.In the following reaction, how many elimination products would be formed in principle by E2 mechanism?a)2b)3c)4d)5Correct answer is option 'D'. Can you explain this answer?, a detailed solution for Passage IIIn an E2 reaction, following one step mechanism is involved.As shown in the above mechanism, aβ-proton anti to leaving group is abstracted by the alkoxide base. If a less bulky base is used, β-proton is eliminated giving most substituted, most stable product as the major product. On the otherhand if a bulky base is used, β-proton is abstracted from β-carbon where there is least steric hindrance and this gives least substituted, although least stable, alkene as the major product.Q.In the following reaction, how many elimination products would be formed in principle by E2 mechanism?a)2b)3c)4d)5Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of Passage IIIn an E2 reaction, following one step mechanism is involved.As shown in the above mechanism, aβ-proton anti to leaving group is abstracted by the alkoxide base. If a less bulky base is used, β-proton is eliminated giving most substituted, most stable product as the major product. On the otherhand if a bulky base is used, β-proton is abstracted from β-carbon where there is least steric hindrance and this gives least substituted, although least stable, alkene as the major product.Q.In the following reaction, how many elimination products would be formed in principle by E2 mechanism?a)2b)3c)4d)5Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Passage IIIn an E2 reaction, following one step mechanism is involved.As shown in the above mechanism, aβ-proton anti to leaving group is abstracted by the alkoxide base. If a less bulky base is used, β-proton is eliminated giving most substituted, most stable product as the major product. On the otherhand if a bulky base is used, β-proton is abstracted from β-carbon where there is least steric hindrance and this gives least substituted, although least stable, alkene as the major product.Q.In the following reaction, how many elimination products would be formed in principle by E2 mechanism?a)2b)3c)4d)5Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 12 tests.

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