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PASSAGE 1
The coordination number of Ni2+ is 4.
NiCl2 + KCN (excess) → A (cyano complex)
NiCl2 + Conc . HCl (excess) → B (chloro complex)
Q. Predict the magnetic nature of A and B
  • a)
    Both are diamagnetic
  • b)
    A is diamagnetic and B is paramagnetic with one unpaired electron
  • c)
    A is diamagnetic and B is paramagnetic with two unpaired electrons
  • d)
    Both are paramagnetic
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
PASSAGE 1The coordination number of Ni2+ is 4.NiCl2 + KCN (excess) &ra...
However, CN is a strong field ligand so it forces the 3d electrons to pair up and hence the effective configuration in this case will be Ni2+ in presence of CN

Thus [Ni (CN)4]2– exhibits dsp2 hybridization and square planar shape. Since here number of unpaired electrons is zero the complex will be diamagnetic.
In case of [NiCl4]2–, Cl is a weak field ligand, so the effective configuration of Ni2+ in this complex will be as follows : Ni2+ in presence of Cl
So here Ni2+ is sp3 hybridised and thus tetrahedral in shape. Since the complex has two unpaired electrons, it will be paramagnetic.
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Most Upvoted Answer
PASSAGE 1The coordination number of Ni2+ is 4.NiCl2 + KCN (excess) &ra...
The coordination number of an ion or atom refers to the number of atoms or ions that surround it in a crystal lattice or complex. In this case, the coordination number of Ni2+ is 4.

NiCl2 is a compound where one Ni2+ ion is surrounded by two Cl- ions, giving it a coordination number of 4. The two chloride ions are coordinated to the nickel ion, forming a square planar geometry.

When excess KCN (potassium cyanide) is added to the NiCl2 solution, a complex called Ni(CN)4^2- is formed. In this complex, the nickel ion is surrounded by four cyanide ions (CN-), giving it a coordination number of 4. The four cyanide ions are coordinated to the nickel ion, forming a tetrahedral geometry.
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PASSAGE 1The coordination number of Ni2+ is 4.NiCl2 + KCN (excess) → A (cyano complex)NiCl2 + Conc . HCl (excess) → B (chloro complex)Q.Predict the magnetic nature of A and Ba)Both are diamagneticb)A is diamagnetic and B is paramagnetic with one unpaired electronc)A is diamagnetic and B is paramagnetic with two unpaired electronsd)Both are paramagneticCorrect answer is option 'C'. Can you explain this answer?
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PASSAGE 1The coordination number of Ni2+ is 4.NiCl2 + KCN (excess) → A (cyano complex)NiCl2 + Conc . HCl (excess) → B (chloro complex)Q.Predict the magnetic nature of A and Ba)Both are diamagneticb)A is diamagnetic and B is paramagnetic with one unpaired electronc)A is diamagnetic and B is paramagnetic with two unpaired electronsd)Both are paramagneticCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about PASSAGE 1The coordination number of Ni2+ is 4.NiCl2 + KCN (excess) → A (cyano complex)NiCl2 + Conc . HCl (excess) → B (chloro complex)Q.Predict the magnetic nature of A and Ba)Both are diamagneticb)A is diamagnetic and B is paramagnetic with one unpaired electronc)A is diamagnetic and B is paramagnetic with two unpaired electronsd)Both are paramagneticCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for PASSAGE 1The coordination number of Ni2+ is 4.NiCl2 + KCN (excess) → A (cyano complex)NiCl2 + Conc . HCl (excess) → B (chloro complex)Q.Predict the magnetic nature of A and Ba)Both are diamagneticb)A is diamagnetic and B is paramagnetic with one unpaired electronc)A is diamagnetic and B is paramagnetic with two unpaired electronsd)Both are paramagneticCorrect answer is option 'C'. Can you explain this answer?.
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