Following compound when heated in ethanol, SN1 reaction occur involving rearrangement of carbocation.Q.In the major product, how many carbon atoms are present in the single largest ring?Correct answer is '6'. Can you explain this answer?

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Following compound when heated in ethanol, S_N1 reaction occur involving rearrangement of carbocation.

In the major product, how many carbon atoms are present in the single largest ring?

Correct answer is '6'. Can you explain this answer?

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Read the passage given below and answer the following questions:Reductive alkylation is the term applied to the process of introducing alkyl groups into ammonia or a primary or secondary amine by means of an aldehyde or ketone in the presence of a reducing agent. The present discussion is limited to those reductive alkylations in which the reducing agent is hydrogen and a catalyst or "nascent" hydrogen, usually from a metalacid combination; most of these reductive alkylations have been carried out with hydrogen and a catalyst. The principal variation excluded is that in which the reducing agent is formic acid or one of its derivatives; this modification is known as the Leuckart reaction. The process of reductive alkylation of ammonia consists in the addition of ammonia to a carbonyl compound and reduction of the addition compound or its dehydration product. The reaction usually is carried out in ethanol solution when the reduction is to be effected catalytically:Since the primary amine is formed in the presence of the aldehyde it may react in the same way as ammonia, yielding an additional compound, a Schiff's base (RCH= NCH2R) and finally, a secondary amine. Similarly, the primary amine may react with the imine, forming an addition product which also is reduced to a secondary amine Finally, the secondary amine may react with either the aldehyde or the imine to give products which are reduced to tertiary amines.Similar reactions may occur when the carbonyl compound employed is a ketone.Q. The reaction of ammonia and its derivatives with aldehydes is called

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Passage IIWhen compound 1 is heated with C2H5ONa compound 2 and 3 are formed:Two mechanisms were proposed for reaction I.Mechanism A HBr is eliminated from compound 1 to form a symmetrical vinyl carbene intermediate A, which then rearranges to compound 2.Mechanism B Ethoxide ion first abstract a proton to form a carbanion intermediate B which then rearranges with loss of bromide ion to form compound 2To distinguish between the two machanisms, an isotopic labeling experiment was designed. Two compounds (Compound 4 and 5) were labelled with C-14 and each was treated separately with sodium ethoxide under identical experimental condition where following results were obtained.Q.In reaction scheme 1, had the α-C to bromine be labelled with C-14

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Following compound when heated in ethanol, SN1 reaction occur involving rearrangement of carbocation.Q.In the major product, how many carbon atoms are present in the single largest ring?Correct answer is '6'. Can you explain this answer?

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