The area bounded by curves y = f(x), the x-axis and the ordinates x = ...
1. Area bounded by curve y = f(x), x =1 and x = b is
Now differentiating both sides with respect to b we get
fB. = sin (3b + 4) + 3(b – 1) cos (3b + 4)
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The area bounded by curves y = f(x), the x-axis and the ordinates x = ...
The correct answer is c) sin(3x - 4).
To find the area bounded by the curves y = f(x), the x-axis, and the ordinates x = 1 and x = b, we need to integrate the function f(x) over the interval [1, b].
The formula for the area bounded by a curve y = f(x) and the x-axis over the interval [a, b] is given by the definite integral:
Area = ∫[a, b] f(x) dx
In this case, the given area is (b - 1) sin(3b - 4). Therefore, we need to find a function f(x) such that:
∫[1, b] f(x) dx = (b - 1) sin(3b - 4)
Taking the derivative of both sides with respect to x, we get:
f(x) = d/dx [(b - 1) sin(3b - 4)]
Using the chain rule, the derivative of (b - 1) sin(3b - 4) with respect to x is:
f(x) = (b - 1) cos(3b - 4) * d/dx (3b - 4)
Since d/dx (3b - 4) = 3, we can simplify the expression further:
f(x) = (b - 1) cos(3b - 4) * 3
Simplifying, we get:
f(x) = 3(b - 1) cos(3b - 4)
However, this does not match any of the answer choices. Therefore, the given information is either incorrect or incomplete, and we cannot determine the exact function f(x) with the given information.