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A designer chooses the values of fluid flow ranges and specific heats insuch a manner that the heat capacities of the two fluids are equal. Ahot fluid enters the counter flow heat exchanger at 100°C and leaves at60°C. The cold fluid enters the heat exchanger at 40°C. The mean temperature difference between the two fluids is:
- a)(100 +60 + 40)/3°C
- b)60°C
- c)40°C
- d)20°C
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A designer chooses the values of fluid flow ranges and specific heats ...
Ans. (d) Mean temperature difference
= Temperature of hot fluid at exit – Temperature of cold fluid at entry
= 60° – 40° = 20°C
= Temperature of hot fluid at exit – Temperature of cold fluid at entry
= 60° – 40° = 20°C
Most Upvoted Answer
A designer chooses the values of fluid flow ranges and specific heats ...
Explanation:
Given:
- Hot fluid enters the counter flow heat exchanger at 100°C and leaves at 60°C.
- Cold fluid enters the heat exchanger at 40°C.
To find the mean temperature difference between the two fluids, we can use the formula:
Mean Temperature Difference (ΔTm) = (Th2 - Tc2) / ln((Th1 - Tc1) / (Th2 - Tc2))
Where:
- Th1 and Tc1 are the temperatures at the hot and cold fluid inlets respectively.
- Th2 and Tc2 are the temperatures at the hot and cold fluid outlets respectively.
Calculation:
Given:
- Th1 = 100°C
- Th2 = 60°C
- Tc1 = 40°C
We can substitute these values into the formula to find ΔTm:
ΔTm = (60 - 40) / ln((100 - 40) / (60 - 40))
= 20 / ln(60 / 20)
= 20 / ln(3)
Using a calculator, we can evaluate this expression to find the approximate value of ΔTm:
ΔTm ≈ 20 / 1.0986
≈ 18.18°C
Therefore, the mean temperature difference between the two fluids is approximately 18.18°C.
Answer:
The correct answer is option (D) 20°C.
Given:
- Hot fluid enters the counter flow heat exchanger at 100°C and leaves at 60°C.
- Cold fluid enters the heat exchanger at 40°C.
To find the mean temperature difference between the two fluids, we can use the formula:
Mean Temperature Difference (ΔTm) = (Th2 - Tc2) / ln((Th1 - Tc1) / (Th2 - Tc2))
Where:
- Th1 and Tc1 are the temperatures at the hot and cold fluid inlets respectively.
- Th2 and Tc2 are the temperatures at the hot and cold fluid outlets respectively.
Calculation:
Given:
- Th1 = 100°C
- Th2 = 60°C
- Tc1 = 40°C
We can substitute these values into the formula to find ΔTm:
ΔTm = (60 - 40) / ln((100 - 40) / (60 - 40))
= 20 / ln(60 / 20)
= 20 / ln(3)
Using a calculator, we can evaluate this expression to find the approximate value of ΔTm:
ΔTm ≈ 20 / 1.0986
≈ 18.18°C
Therefore, the mean temperature difference between the two fluids is approximately 18.18°C.
Answer:
The correct answer is option (D) 20°C.
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A designer chooses the values of fluid flow ranges and specific heats insuch a manner that the heat capacities of the two fluids are equal. Ahot fluid enters the counter flow heat exchanger at 100°C and leaves at60°C. The cold fluid enters the heat exchanger at 40°C. The mean temperature difference between the two fluids is:a)(100 +60 + 40)/3°Cb)60°Cc)40°Cd)20°CCorrect answer is option 'D'. Can you explain this answer?
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