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One Integer Value Correct Type
Direction (Q. Nos. 17 and 18) This section contains 2 questions. When worked out will result in an integer from 0 to 9 (both inclusive).
Q.
If meso form of the 2,4-dibromopentane is treated with excess of KCN(aq), how many SN2 products with both bromide substituted, wouid result?
Correct answer is '4'. Can you explain this answer?
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One Integer Value Correct TypeDirection (Q. Nos. 17and 18) This sectio...
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Answer:
To determine the number of SN2 products with both bromide substituted when the meso form of 2,4-dibromopentane is treated with excess KCN(aq), we need to consider the stereochemistry and reactivity of the compound.
Stereochemistry of 2,4-dibromopentane:
The meso form of 2,4-dibromopentane has a plane of symmetry, which means it is an achiral compound. The carbon atom with the bromine substituents is also a chiral center, but its two enantiomers in the meso form are superimposable. Therefore, there is no optical activity in the meso form.
KCN(aq) as a nucleophile:
KCN(aq) is a strong nucleophile, and it attacks the electrophilic carbon atom in SN2 reactions. The reaction proceeds via a backside attack, resulting in inversion of configuration at the chiral center.
Number of SN2 products:
When the meso form of 2,4-dibromopentane is treated with excess KCN(aq), there are four possible SN2 products with both bromide substituted. This can be explained as follows:
1. The nucleophile can attack the carbon atom from the front side, resulting in inversion of configuration. This leads to two different products due to the presence of two bromine substituents on the carbon atom.
2. The nucleophile can attack the carbon atom from the back side, also resulting in inversion of configuration. This also leads to two different products due to the presence of two bromine substituents on the carbon atom.
Therefore, the total number of SN2 products with both bromide substituted is 2 + 2 = 4.
Summary:
When the meso form of 2,4-dibromopentane is treated with excess KCN(aq), there are four possible SN2 products with both bromide substituted. The reaction proceeds via a backside attack by the nucleophile, resulting in inversion of configuration at the chiral center. The plane of symmetry in the meso form ensures that the two enantiomers are superimposable and there is no optical activity.
To determine the number of SN2 products with both bromide substituted when the meso form of 2,4-dibromopentane is treated with excess KCN(aq), we need to consider the stereochemistry and reactivity of the compound.
Stereochemistry of 2,4-dibromopentane:
The meso form of 2,4-dibromopentane has a plane of symmetry, which means it is an achiral compound. The carbon atom with the bromine substituents is also a chiral center, but its two enantiomers in the meso form are superimposable. Therefore, there is no optical activity in the meso form.
KCN(aq) as a nucleophile:
KCN(aq) is a strong nucleophile, and it attacks the electrophilic carbon atom in SN2 reactions. The reaction proceeds via a backside attack, resulting in inversion of configuration at the chiral center.
Number of SN2 products:
When the meso form of 2,4-dibromopentane is treated with excess KCN(aq), there are four possible SN2 products with both bromide substituted. This can be explained as follows:
1. The nucleophile can attack the carbon atom from the front side, resulting in inversion of configuration. This leads to two different products due to the presence of two bromine substituents on the carbon atom.
2. The nucleophile can attack the carbon atom from the back side, also resulting in inversion of configuration. This also leads to two different products due to the presence of two bromine substituents on the carbon atom.
Therefore, the total number of SN2 products with both bromide substituted is 2 + 2 = 4.
Summary:
When the meso form of 2,4-dibromopentane is treated with excess KCN(aq), there are four possible SN2 products with both bromide substituted. The reaction proceeds via a backside attack by the nucleophile, resulting in inversion of configuration at the chiral center. The plane of symmetry in the meso form ensures that the two enantiomers are superimposable and there is no optical activity.
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One Integer Value Correct TypeDirection (Q. Nos. 17and 18) This section contains 2 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If meso form of the 2,4-dibromopentane is treated with excess of KCN(aq), how many SN2 products with both bromide substituted, wouid result?Correct answer is '4'. Can you explain this answer?
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One Integer Value Correct TypeDirection (Q. Nos. 17and 18) This section contains 2 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If meso form of the 2,4-dibromopentane is treated with excess of KCN(aq), how many SN2 products with both bromide substituted, wouid result?Correct answer is '4'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One Integer Value Correct TypeDirection (Q. Nos. 17and 18) This section contains 2 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If meso form of the 2,4-dibromopentane is treated with excess of KCN(aq), how many SN2 products with both bromide substituted, wouid result?Correct answer is '4'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One Integer Value Correct TypeDirection (Q. Nos. 17and 18) This section contains 2 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If meso form of the 2,4-dibromopentane is treated with excess of KCN(aq), how many SN2 products with both bromide substituted, wouid result?Correct answer is '4'. Can you explain this answer?.
One Integer Value Correct TypeDirection (Q. Nos. 17and 18) This section contains 2 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If meso form of the 2,4-dibromopentane is treated with excess of KCN(aq), how many SN2 products with both bromide substituted, wouid result?Correct answer is '4'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One Integer Value Correct TypeDirection (Q. Nos. 17and 18) This section contains 2 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If meso form of the 2,4-dibromopentane is treated with excess of KCN(aq), how many SN2 products with both bromide substituted, wouid result?Correct answer is '4'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One Integer Value Correct TypeDirection (Q. Nos. 17and 18) This section contains 2 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If meso form of the 2,4-dibromopentane is treated with excess of KCN(aq), how many SN2 products with both bromide substituted, wouid result?Correct answer is '4'. Can you explain this answer?.
Solutions for One Integer Value Correct TypeDirection (Q. Nos. 17and 18) This section contains 2 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If meso form of the 2,4-dibromopentane is treated with excess of KCN(aq), how many SN2 products with both bromide substituted, wouid result?Correct answer is '4'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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