Water is flowing at the rate of 3 km/hr through a circular pipe of 20 ...
Solution:
Given:
- The water is flowing at the rate of 3 km/hr through a circular pipe.
- The internal diameter of the pipe is 20 cm.
- The circular cistern has a diameter of 10 m and a depth of 2 m.
We need to find the time taken to fill the cistern.
First, let's convert the flow rate from km/hr to m/s.
- 3 km/hr = 3000 m/3600 s = 5/6 m/s
Now, let's calculate the area of the pipe and the cistern.
- Area of the pipe = πr^2 = π(20/2)^2 = π(10)^2 = 100π cm^2
- Area of the cistern = πr^2 = π(100/2)^2 = π(50)^2 = 2500π m^2
Next, let's calculate the volume of water flowing through the pipe per second.
- Volume per second = (Area of the pipe) * (flow rate) = (100π cm^2) * (5/6 m/s) = (500/3)π cm^3/s
Now, let's convert the volume per second to volume per hour.
- Volume per hour = (Volume per second) * (3600 s/hr) = (500/3)π cm^3/s * 3600 s/hr = (60000/3)π cm^3/hr
Next, let's calculate the volume of the cistern.
- Volume of the cistern = (Area of the cistern) * (depth of the cistern) = (2500π m^2) * (2 m) = (5000π) m^3
Finally, let's calculate the time taken to fill the cistern.
- Time taken = (Volume of the cistern) / (Volume per hour) = [(5000π) m^3] / [(60000/3)π cm^3/hr]
- Simplifying, we get: Time taken = (5000 * 3) / 60000 = 250 / 12 = 20.83 hours
Since the options provided are in hours and minutes, we need to convert the decimal part of the time into minutes.
- 0.83 hours = 0.83 * 60 minutes = 49.8 minutes ≈ 50 minutes
Therefore, the cistern will be filled in approximately 20 hours and 50 minutes, which is closest to option B) 1 hour 40 minutes.