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If nth term of a series is 3•2^n-4,find the sum of it's 100 term?
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If nth term of a series is 3•2^n-4,find the sum of it's 100 term?
**Finding the nth Term of the Series**

To find the sum of the 100 terms of the given series, we first need to determine the formula for the nth term. The given series is expressed as 3 • 2^n-4.

We can break down the given expression to understand it better:
- The base of the exponent is 2, indicating that the series is a geometric series.
- The coefficient 3 indicates that each term of the series is multiplied by 3.
- The term 2^n-4 signifies that each term in the series is obtained by raising 2 to the power of (n-4).

Let's expand the expression to understand it further:
- The first term (n=1) can be calculated as: 3 • 2^(1-4) = 3 • 2^-3 = 3/2^3 = 3/8.
- The second term (n=2) can be calculated as: 3 • 2^(2-4) = 3 • 2^-2 = 3/2^2 = 3/4.
- The third term (n=3) can be calculated as: 3 • 2^(3-4) = 3 • 2^-1 = 3/2^1 = 3/2.

From the above calculations, we can observe a pattern: each term of the series is obtained by dividing 3 by a power of 2.

**Finding the Sum of the Series**

To find the sum of the series, we need to use the formula for the sum of a geometric series. The formula is given as:

S = a(1 - r^n) / (1 - r)

Where:
- S is the sum of the series
- a is the first term of the series
- r is the common ratio
- n is the number of terms in the series

In our case:
- a = 3/8 (the first term)
- r = 1/2 (the common ratio, obtained by dividing each term by the previous one)
- n = 100 (the number of terms)

Using the formula, we can calculate the sum of the series:
S = (3/8) * (1 - (1/2)^100) / (1 - 1/2)

Simplifying the expression further will provide the sum of the 100 terms of the given series.
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