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If the plank’s constant would be double the present value, in the Bohr’s model for hydrogen atom
  • a)
    the speed of the electron in the ground state would be halved
  • b)
    the radius of electronic orbit in the ground state would be four times
  • c)
    the energy required to ionize the hydrogen atom in the ground state would be doubled
  • d)
    the angular momentum of the electron in the ground state would be doubled
Correct answer is option 'A,B,D'. Can you explain this answer?
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Effect of doubling the Planck's constant in Bohr's model for hydrogen atom:



Speed of the electron in the ground state:
- If the Planck's constant is doubled, the speed of the electron in the ground state would be halved. This is because the speed of the electron is inversely proportional to the Planck's constant in Bohr's model.

Radius of electronic orbit in the ground state:
- Doubling the Planck's constant would result in the radius of the electronic orbit in the ground state being four times larger. This is because the radius is directly proportional to the square of the Planck's constant in Bohr's model.

Energy required to ionize the hydrogen atom in the ground state:
- The energy required to ionize the hydrogen atom in the ground state would be doubled if the Planck's constant is doubled. This is because the ionization energy is directly proportional to the Planck's constant in Bohr's model.

Angular momentum of the electron in the ground state:
- Doubling the Planck's constant would result in the angular momentum of the electron in the ground state being doubled. This is because the angular momentum is directly proportional to the Planck's constant in Bohr's model.

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If the plank’s constant would be double the present value, in the Bohr’s model for hydrogen atoma)the speed of the electron in the ground state would be halvedb)the radius of electronic orbit in the ground state would be four timesc)the energy required to ionize the hydrogen atom in the ground state would be doubledd)the angular momentum of the electron in the ground state would be doubledCorrect answer is option 'A,B,D'. Can you explain this answer?
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