Study the given letter series and answer the questions that follow:H D...
Understanding the Problem
To find which two neighbors in the given letter series are the farthest apart in the alphabetical order, we first need to analyze the series:
H, D, Y, S, M, W, N, B, Q, P, O, C, R, T, B, L, Z, V, E, G, U, F, Q.
Identifying the Options
The options provided are:
a) V and G
b) B and P
c) D and Y
d) B and O
Analyzing the Alphabetical Distances
Now, let's calculate the alphabetical positions of the relevant letters:
- **D** is the 4th letter, and **Y** is the 25th letter.
- Distance: |25 - 4| = 21
- **V** is the 22nd letter, and **G** is the 7th letter.
- Distance: |22 - 7| = 15
- **B** is the 2nd letter, and **P** is the 16th letter.
- Distance: |16 - 2| = 14
- **B** is the 2nd letter, and **O** is the 15th letter.
- Distance: |15 - 2| = 13
Conclusion
From the calculations, we see that:
- D and Y have the farthest distance of 21 letters apart in the alphabet.
- The other pairs have smaller distances: V and G (15), B and P (14), and B and O (13).
Thus, the correct answer is option **C**: D and Y.