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Block ‘A’ of mass m is hanging from a vertical spring of spring constant k and is at rest. The value of m/k = 1/150SIunits. Block ‘B’ also of mass m strikes the block ‘A’ with velocity ‘v’ and sticks to it. Then find the value of ‘v’ in m/sfor which the spring just attains natural length. Takeg=10m/s2Correct answer is '2'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Block ‘A’ of mass m is hanging from a vertical spring of spring constant k and is at rest. The value of m/k = 1/150SIunits. Block ‘B’ also of mass m strikes the block ‘A’ with velocity ‘v’ and sticks to it. Then find the value of ‘v’ in m/sfor which the spring just attains natural length. Takeg=10m/s2Correct answer is '2'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Block ‘A’ of mass m is hanging from a vertical spring of spring constant k and is at rest. The value of m/k = 1/150SIunits. Block ‘B’ also of mass m strikes the block ‘A’ with velocity ‘v’ and sticks to it. Then find the value of ‘v’ in m/sfor which the spring just attains natural length. Takeg=10m/s2Correct answer is '2'. Can you explain this answer?.

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Here you can find the meaning of Block ‘A’ of mass m is hanging from a vertical spring of spring constant k and is at rest. The value of m/k = 1/150SIunits. Block ‘B’ also of mass m strikes the block ‘A’ with velocity ‘v’ and sticks to it. Then find the value of ‘v’ in m/sfor which the spring just attains natural length. Takeg=10m/s2Correct answer is '2'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Block ‘A’ of mass m is hanging from a vertical spring of spring constant k and is at rest. The value of m/k = 1/150SIunits. Block ‘B’ also of mass m strikes the block ‘A’ with velocity ‘v’ and sticks to it. Then find the value of ‘v’ in m/sfor which the spring just attains natural length. Takeg=10m/s2Correct answer is '2'. Can you explain this answer?, a detailed solution for Block ‘A’ of mass m is hanging from a vertical spring of spring constant k and is at rest. The value of m/k = 1/150SIunits. Block ‘B’ also of mass m strikes the block ‘A’ with velocity ‘v’ and sticks to it. Then find the value of ‘v’ in m/sfor which the spring just attains natural length. Takeg=10m/s2Correct answer is '2'. Can you explain this answer? has been provided alongside types of Block ‘A’ of mass m is hanging from a vertical spring of spring constant k and is at rest. The value of m/k = 1/150SIunits. Block ‘B’ also of mass m strikes the block ‘A’ with velocity ‘v’ and sticks to it. Then find the value of ‘v’ in m/sfor which the spring just attains natural length. Takeg=10m/s2Correct answer is '2'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Block ‘A’ of mass m is hanging from a vertical spring of spring constant k and is at rest. The value of m/k = 1/150SIunits. Block ‘B’ also of mass m strikes the block ‘A’ with velocity ‘v’ and sticks to it. Then find the value of ‘v’ in m/sfor which the spring just attains natural length. Takeg=10m/s2Correct answer is '2'. Can you explain this answer? tests, examples and also practice JEE tests.