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A block is thrown with a velocity of 2 ms-1 (relative to ground) on a belt, which is moving with velocity 4 ms-1 in opposite direction of the initial velocity of block. If the block stops slipping on the belt after 4 sec of the throwing then choose the correct statements(s)
- a)Displacement with respect to ground is zero after 2.66 sec and magnitude of displacement with respect to ground is 12 m after 4 sec.
- b)Magnitude of displacement with respect to ground in 4 sec is 4 m.
- c)Magnitude of displacement with respect to belt in 4 sec is 12 m.
- d)Displacement with respect to ground is zero in 8/3 sec
Correct answer is option 'B,C,D'. Can you explain this answer?
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Verified Answer
A block is thrown with a velocity of 2 ms-1(relative to ground) on a b...
ATQ: u = 2 m/s, v = -4 m/s, so,
Now, to find the time at which the displacement is zero
Now, to find the displacement at time t = 4 secs wrt the ground
And the displacement at time t = 4 secs wrt the belt
Now, to find the time at which the displacement is zero
Now, to find the displacement at time t = 4 secs wrt the ground
And the displacement at time t = 4 secs wrt the belt
Most Upvoted Answer
A block is thrown with a velocity of 2 ms-1(relative to ground) on a b...
Explanation:
To solve this problem, we need to analyze the motion of the block with respect to both the belt and the ground.
Motion with respect to the belt:
The initial velocity of the block with respect to the belt is the difference between the block's velocity and the belt's velocity.
Relative velocity of block with respect to belt = 2 m/s - (-4 m/s) = 6 m/s
Since the block comes to rest after 4 seconds, the acceleration with respect to the belt can be calculated using the formula:
Final velocity = Initial velocity + (acceleration * time)
0 m/s = 6 m/s + (acceleration * 4 s)
Solving this equation, we get the acceleration with respect to the belt as -1.5 m/s^2.
Using this acceleration, we can calculate the displacement of the block with respect to the belt using the formula:
Displacement = (Initial velocity * time) + (0.5 * acceleration * time^2)
Displacement = (6 m/s * 4 s) + (0.5 * -1.5 m/s^2 * (4 s)^2)
Displacement = 24 m - 12 m = 12 m
Motion with respect to the ground:
The velocity of the belt is subtracted from the velocity of the block to determine the block's velocity with respect to the ground.
Velocity of block with respect to ground = 2 m/s - 4 m/s = -2 m/s (opposite direction to the belt)
The displacement of the block with respect to the ground is calculated using the formula:
Displacement = (Initial velocity * time) + (0.5 * acceleration * time^2)
Displacement = (-2 m/s * 4 s) + (0.5 * 0 * (4 s)^2)
Displacement = -8 m + 0 m = -8 m
Conclusion:
Based on the calculations, we can conclude the following statements:
b) Magnitude of displacement with respect to ground in 4 sec is 4 m.
c) Magnitude of displacement with respect to belt in 4 sec is 12 m.
d) Displacement with respect to ground is zero in 8/3 sec
These statements are correct based on the analysis of the block's motion with respect to both the belt and the ground.
To solve this problem, we need to analyze the motion of the block with respect to both the belt and the ground.
Motion with respect to the belt:
The initial velocity of the block with respect to the belt is the difference between the block's velocity and the belt's velocity.
Relative velocity of block with respect to belt = 2 m/s - (-4 m/s) = 6 m/s
Since the block comes to rest after 4 seconds, the acceleration with respect to the belt can be calculated using the formula:
Final velocity = Initial velocity + (acceleration * time)
0 m/s = 6 m/s + (acceleration * 4 s)
Solving this equation, we get the acceleration with respect to the belt as -1.5 m/s^2.
Using this acceleration, we can calculate the displacement of the block with respect to the belt using the formula:
Displacement = (Initial velocity * time) + (0.5 * acceleration * time^2)
Displacement = (6 m/s * 4 s) + (0.5 * -1.5 m/s^2 * (4 s)^2)
Displacement = 24 m - 12 m = 12 m
Motion with respect to the ground:
The velocity of the belt is subtracted from the velocity of the block to determine the block's velocity with respect to the ground.
Velocity of block with respect to ground = 2 m/s - 4 m/s = -2 m/s (opposite direction to the belt)
The displacement of the block with respect to the ground is calculated using the formula:
Displacement = (Initial velocity * time) + (0.5 * acceleration * time^2)
Displacement = (-2 m/s * 4 s) + (0.5 * 0 * (4 s)^2)
Displacement = -8 m + 0 m = -8 m
Conclusion:
Based on the calculations, we can conclude the following statements:
b) Magnitude of displacement with respect to ground in 4 sec is 4 m.
c) Magnitude of displacement with respect to belt in 4 sec is 12 m.
d) Displacement with respect to ground is zero in 8/3 sec
These statements are correct based on the analysis of the block's motion with respect to both the belt and the ground.
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A block is thrown with a velocity of 2 ms-1(relative to ground) on a b...
C options is correct
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A block is thrown with a velocity of 2 ms-1(relative to ground) on a belt, which is moving with velocity 4 ms-1in opposite direction of the initial velocity of block. If the block stops slipping on the belt after 4 sec of the throwing then choose the correct statements(s)a)Displacement with respect to ground is zero after 2.66 sec and magnitude of displacement with respect to ground is 12 m after 4 sec.b)Magnitude of displacement with respect to ground in 4 sec is 4 m.c)Magnitude of displacement with respect to belt in 4 sec is 12 m.d)Displacement with respect to ground is zero in 8/3 secCorrect answer is option 'B,C,D'. Can you explain this answer?
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A block is thrown with a velocity of 2 ms-1(relative to ground) on a belt, which is moving with velocity 4 ms-1in opposite direction of the initial velocity of block. If the block stops slipping on the belt after 4 sec of the throwing then choose the correct statements(s)a)Displacement with respect to ground is zero after 2.66 sec and magnitude of displacement with respect to ground is 12 m after 4 sec.b)Magnitude of displacement with respect to ground in 4 sec is 4 m.c)Magnitude of displacement with respect to belt in 4 sec is 12 m.d)Displacement with respect to ground is zero in 8/3 secCorrect answer is option 'B,C,D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A block is thrown with a velocity of 2 ms-1(relative to ground) on a belt, which is moving with velocity 4 ms-1in opposite direction of the initial velocity of block. If the block stops slipping on the belt after 4 sec of the throwing then choose the correct statements(s)a)Displacement with respect to ground is zero after 2.66 sec and magnitude of displacement with respect to ground is 12 m after 4 sec.b)Magnitude of displacement with respect to ground in 4 sec is 4 m.c)Magnitude of displacement with respect to belt in 4 sec is 12 m.d)Displacement with respect to ground is zero in 8/3 secCorrect answer is option 'B,C,D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block is thrown with a velocity of 2 ms-1(relative to ground) on a belt, which is moving with velocity 4 ms-1in opposite direction of the initial velocity of block. If the block stops slipping on the belt after 4 sec of the throwing then choose the correct statements(s)a)Displacement with respect to ground is zero after 2.66 sec and magnitude of displacement with respect to ground is 12 m after 4 sec.b)Magnitude of displacement with respect to ground in 4 sec is 4 m.c)Magnitude of displacement with respect to belt in 4 sec is 12 m.d)Displacement with respect to ground is zero in 8/3 secCorrect answer is option 'B,C,D'. Can you explain this answer?.
A block is thrown with a velocity of 2 ms-1(relative to ground) on a belt, which is moving with velocity 4 ms-1in opposite direction of the initial velocity of block. If the block stops slipping on the belt after 4 sec of the throwing then choose the correct statements(s)a)Displacement with respect to ground is zero after 2.66 sec and magnitude of displacement with respect to ground is 12 m after 4 sec.b)Magnitude of displacement with respect to ground in 4 sec is 4 m.c)Magnitude of displacement with respect to belt in 4 sec is 12 m.d)Displacement with respect to ground is zero in 8/3 secCorrect answer is option 'B,C,D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A block is thrown with a velocity of 2 ms-1(relative to ground) on a belt, which is moving with velocity 4 ms-1in opposite direction of the initial velocity of block. If the block stops slipping on the belt after 4 sec of the throwing then choose the correct statements(s)a)Displacement with respect to ground is zero after 2.66 sec and magnitude of displacement with respect to ground is 12 m after 4 sec.b)Magnitude of displacement with respect to ground in 4 sec is 4 m.c)Magnitude of displacement with respect to belt in 4 sec is 12 m.d)Displacement with respect to ground is zero in 8/3 secCorrect answer is option 'B,C,D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block is thrown with a velocity of 2 ms-1(relative to ground) on a belt, which is moving with velocity 4 ms-1in opposite direction of the initial velocity of block. If the block stops slipping on the belt after 4 sec of the throwing then choose the correct statements(s)a)Displacement with respect to ground is zero after 2.66 sec and magnitude of displacement with respect to ground is 12 m after 4 sec.b)Magnitude of displacement with respect to ground in 4 sec is 4 m.c)Magnitude of displacement with respect to belt in 4 sec is 12 m.d)Displacement with respect to ground is zero in 8/3 secCorrect answer is option 'B,C,D'. Can you explain this answer?.
Solutions for A block is thrown with a velocity of 2 ms-1(relative to ground) on a belt, which is moving with velocity 4 ms-1in opposite direction of the initial velocity of block. If the block stops slipping on the belt after 4 sec of the throwing then choose the correct statements(s)a)Displacement with respect to ground is zero after 2.66 sec and magnitude of displacement with respect to ground is 12 m after 4 sec.b)Magnitude of displacement with respect to ground in 4 sec is 4 m.c)Magnitude of displacement with respect to belt in 4 sec is 12 m.d)Displacement with respect to ground is zero in 8/3 secCorrect answer is option 'B,C,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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Here you can find the meaning of A block is thrown with a velocity of 2 ms-1(relative to ground) on a belt, which is moving with velocity 4 ms-1in opposite direction of the initial velocity of block. If the block stops slipping on the belt after 4 sec of the throwing then choose the correct statements(s)a)Displacement with respect to ground is zero after 2.66 sec and magnitude of displacement with respect to ground is 12 m after 4 sec.b)Magnitude of displacement with respect to ground in 4 sec is 4 m.c)Magnitude of displacement with respect to belt in 4 sec is 12 m.d)Displacement with respect to ground is zero in 8/3 secCorrect answer is option 'B,C,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A block is thrown with a velocity of 2 ms-1(relative to ground) on a belt, which is moving with velocity 4 ms-1in opposite direction of the initial velocity of block. If the block stops slipping on the belt after 4 sec of the throwing then choose the correct statements(s)a)Displacement with respect to ground is zero after 2.66 sec and magnitude of displacement with respect to ground is 12 m after 4 sec.b)Magnitude of displacement with respect to ground in 4 sec is 4 m.c)Magnitude of displacement with respect to belt in 4 sec is 12 m.d)Displacement with respect to ground is zero in 8/3 secCorrect answer is option 'B,C,D'. Can you explain this answer?, a detailed solution for A block is thrown with a velocity of 2 ms-1(relative to ground) on a belt, which is moving with velocity 4 ms-1in opposite direction of the initial velocity of block. If the block stops slipping on the belt after 4 sec of the throwing then choose the correct statements(s)a)Displacement with respect to ground is zero after 2.66 sec and magnitude of displacement with respect to ground is 12 m after 4 sec.b)Magnitude of displacement with respect to ground in 4 sec is 4 m.c)Magnitude of displacement with respect to belt in 4 sec is 12 m.d)Displacement with respect to ground is zero in 8/3 secCorrect answer is option 'B,C,D'. Can you explain this answer? has been provided alongside types of A block is thrown with a velocity of 2 ms-1(relative to ground) on a belt, which is moving with velocity 4 ms-1in opposite direction of the initial velocity of block. If the block stops slipping on the belt after 4 sec of the throwing then choose the correct statements(s)a)Displacement with respect to ground is zero after 2.66 sec and magnitude of displacement with respect to ground is 12 m after 4 sec.b)Magnitude of displacement with respect to ground in 4 sec is 4 m.c)Magnitude of displacement with respect to belt in 4 sec is 12 m.d)Displacement with respect to ground is zero in 8/3 secCorrect answer is option 'B,C,D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A block is thrown with a velocity of 2 ms-1(relative to ground) on a belt, which is moving with velocity 4 ms-1in opposite direction of the initial velocity of block. If the block stops slipping on the belt after 4 sec of the throwing then choose the correct statements(s)a)Displacement with respect to ground is zero after 2.66 sec and magnitude of displacement with respect to ground is 12 m after 4 sec.b)Magnitude of displacement with respect to ground in 4 sec is 4 m.c)Magnitude of displacement with respect to belt in 4 sec is 12 m.d)Displacement with respect to ground is zero in 8/3 secCorrect answer is option 'B,C,D'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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