A car moving with the velocity of 36km/ h . When brakes are applied it stop after 10m calculate acceleration and time taken to stop ?

Question

Answer

Calculation of Acceleration and Time Taken to Stop a Car

Given:

Initial velocity of the car, u = 36 km/h = 10 m/s

Final velocity of the car, v = 0 km/h = 0 m/s

Distance covered by the car while stopping, s = 10 m

Acceleration:

Acceleration is defined as the rate of change of velocity with respect to time. It is given by the formula:

a = (v - u) / t

where,

a = acceleration

v = final velocity

u = initial velocity

t = time taken

Since the final velocity of the car is zero, the above equation becomes:

a = -u / t

Substituting the given values, we get:

a = -10 / t

Time Taken:

Time taken by the car to stop is given by the formula:

t = 2s / (u + v)

where,

t = time taken

s = distance covered

u = initial velocity

v = final velocity

Substituting the given values, we get:

t = 2 x 10 / (10 + 0) = 2 seconds

Conclusion:

The acceleration of the car is -5 m/s^2

The time taken by the car to stop is 2 seconds

Therefore, the car has a negative acceleration of 5 m/s^2 and it takes 2 seconds to come to a complete stop after applying the brakes.

Answer

Acceralation=5
time=2 sec

Answer

Acceleration =5
time= 2

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