A car moving with the velocity of 36km/ h . When brakes are applied it stop after 10m calculate acceleration and time taken to stop ?

Question

Answer

Calculation of Acceleration and Time Taken to Stop a Car

Given:

Initial velocity of the car, u = 36 km/h = 10 m/s

Final velocity of the car, v = 0 km/h = 0 m/s

Distance covered by the car while stopping, s = 10 m

Acceleration:

Acceleration is defined as the rate of change of velocity with respect to time. It is given by the formula:

a = (v - u) / t

where,

a = acceleration

v = final velocity

u = initial velocity

t = time taken

Since the final velocity of the car is zero, the above equation becomes:

a = -u / t

Substituting the given values, we get:

a = -10 / t

Time Taken:

Time taken by the car to stop is given by the formula:

t = 2s / (u + v)

where,

t = time taken

s = distance covered

u = initial velocity

v = final velocity

Substituting the given values, we get:

t = 2 x 10 / (10 + 0) = 2 seconds

Conclusion:

The acceleration of the car is -5 m/s^2

The time taken by the car to stop is 2 seconds

Therefore, the car has a negative acceleration of 5 m/s^2 and it takes 2 seconds to come to a complete stop after applying the brakes.

Answer

Acceralation=5
time=2 sec

Answer

Acceleration =5
time= 2

Similar Class 11 Doubts

A car mpving with a uniform speed of 20m/sec comes to stop on the applicaton of brakes after travelling a distance of 10m. Its acceleration is ?

A body is moving with velocity 30m/s towards East.after 10 seconds it's velocity becomes 40 m)s towards North. the average acceleration of the body is?

An unloaded and loaded bus are both moving with same kinetic energy. Mass of the lattes is twice as that of former. Brakes are applied to both so as to exert equal retarding force . If x1 and x2 be the distance covered by the two buses before coming to rest then what is relation between x1 and x2

A body moving along a circular path of radius R with velocity v, has centripetal acceleration a, if it's velocity is made equal to 2v, then it's centripetal acceleration is 1) 4a 2) 2a 3) a/4 4) a/2?

Tangential acceleration of a particle moving in a circle of radius 1m varies with time t as ( initial velocity of particle is zero ). Time after which total acceleration of particle makes and angle of 30 degree with radial acceleration is?

Top Courses for Class 11View all

Chemistry Class 11

CUET Mock Test: Humanities Subjects 2025

English Class 11

Mathematics (Maths) Class 11

Psychology Practice Tests: CUET Preparation

Top Courses for Class 11

Top Courses for Class 11

Suggested Free Tests

Related Content

Schools

Competitive Examinations

Quick Access Links

Technical Exams