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In a counter flow heat exchanger, for the hot fluid the heat capacity = 2kJ/kg K, mass flow rate = 5 kg/s, inlet temperature = 150°C, outlet temperature = 100°C. For the cold fluid, heat capacity = 4 kJ/kg K, massflow rate = 10 kg/s, inlet temperature = 20°C. Neglecting heat transfer tothe surroundings, the outlet temperature of the cold fluid in °C is:
- a)7.5
- b)32.5
- c)45.5
- d)70.0
Correct answer is option 'B'. Can you explain this answer?
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In a counter flow heat exchanger, for the hot fluid the heat capacity ...
Ans. (b) Let temperature t°C
Heat loss by hot water = heat gain by cold water
Heat loss by hot water = heat gain by cold water
Most Upvoted Answer
In a counter flow heat exchanger, for the hot fluid the heat capacity ...
Given parameters:
Hot fluid:
- Heat capacity = 2 kJ/kg K
- Mass flow rate = 5 kg/s
- Inlet temperature = 150°C
- Outlet temperature = 100°C
Cold fluid:
- Heat capacity = 4 kJ/kg K
- Mass flow rate = 10 kg/s
- Inlet temperature = 20°C
To find:
Outlet temperature of cold fluid
Solution:
1. Calculate the heat transferred between the hot and cold fluids:
Q = m_hot * C_hot * (T_hot_in - T_hot_out) = m_cold * C_cold * (T_cold_out - T_cold_in)
where
Q = heat transferred
m = mass flow rate
C = specific heat capacity
T = temperature
2. Rearrange the equation to solve for T_cold_out:
T_cold_out = T_cold_in + (m_hot / m_cold) * [C_hot / C_cold] * (T_hot_in - T_hot_out)
3. Plug in the given values and solve for T_cold_out:
T_cold_out = 20 + (5 / 10) * [2 / 4] * (150 - 100) = 32.5°C
Therefore, the outlet temperature of the cold fluid is 32.5°C.
Answer:
Option B.
Hot fluid:
- Heat capacity = 2 kJ/kg K
- Mass flow rate = 5 kg/s
- Inlet temperature = 150°C
- Outlet temperature = 100°C
Cold fluid:
- Heat capacity = 4 kJ/kg K
- Mass flow rate = 10 kg/s
- Inlet temperature = 20°C
To find:
Outlet temperature of cold fluid
Solution:
1. Calculate the heat transferred between the hot and cold fluids:
Q = m_hot * C_hot * (T_hot_in - T_hot_out) = m_cold * C_cold * (T_cold_out - T_cold_in)
where
Q = heat transferred
m = mass flow rate
C = specific heat capacity
T = temperature
2. Rearrange the equation to solve for T_cold_out:
T_cold_out = T_cold_in + (m_hot / m_cold) * [C_hot / C_cold] * (T_hot_in - T_hot_out)
3. Plug in the given values and solve for T_cold_out:
T_cold_out = 20 + (5 / 10) * [2 / 4] * (150 - 100) = 32.5°C
Therefore, the outlet temperature of the cold fluid is 32.5°C.
Answer:
Option B.
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In a counter flow heat exchanger, for the hot fluid the heat capacity = 2kJ/kg K, mass flow rate = 5 kg/s, inlet temperature = 150°C, outlet temperature = 100°C. For the cold fluid, heat capacity = 4 kJ/kg K, massflow rate = 10 kg/s, inlet temperature = 20°C. Neglecting heat transfer tothe surroundings, the outlet temperature of the cold fluid in °C is:a)7.5b)32.5c)45.5d)70.0Correct answer is option 'B'. Can you explain this answer?
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In a counter flow heat exchanger, for the hot fluid the heat capacity = 2kJ/kg K, mass flow rate = 5 kg/s, inlet temperature = 150°C, outlet temperature = 100°C. For the cold fluid, heat capacity = 4 kJ/kg K, massflow rate = 10 kg/s, inlet temperature = 20°C. Neglecting heat transfer tothe surroundings, the outlet temperature of the cold fluid in °C is:a)7.5b)32.5c)45.5d)70.0Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In a counter flow heat exchanger, for the hot fluid the heat capacity = 2kJ/kg K, mass flow rate = 5 kg/s, inlet temperature = 150°C, outlet temperature = 100°C. For the cold fluid, heat capacity = 4 kJ/kg K, massflow rate = 10 kg/s, inlet temperature = 20°C. Neglecting heat transfer tothe surroundings, the outlet temperature of the cold fluid in °C is:a)7.5b)32.5c)45.5d)70.0Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a counter flow heat exchanger, for the hot fluid the heat capacity = 2kJ/kg K, mass flow rate = 5 kg/s, inlet temperature = 150°C, outlet temperature = 100°C. For the cold fluid, heat capacity = 4 kJ/kg K, massflow rate = 10 kg/s, inlet temperature = 20°C. Neglecting heat transfer tothe surroundings, the outlet temperature of the cold fluid in °C is:a)7.5b)32.5c)45.5d)70.0Correct answer is option 'B'. Can you explain this answer?.
In a counter flow heat exchanger, for the hot fluid the heat capacity = 2kJ/kg K, mass flow rate = 5 kg/s, inlet temperature = 150°C, outlet temperature = 100°C. For the cold fluid, heat capacity = 4 kJ/kg K, massflow rate = 10 kg/s, inlet temperature = 20°C. Neglecting heat transfer tothe surroundings, the outlet temperature of the cold fluid in °C is:a)7.5b)32.5c)45.5d)70.0Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In a counter flow heat exchanger, for the hot fluid the heat capacity = 2kJ/kg K, mass flow rate = 5 kg/s, inlet temperature = 150°C, outlet temperature = 100°C. For the cold fluid, heat capacity = 4 kJ/kg K, massflow rate = 10 kg/s, inlet temperature = 20°C. Neglecting heat transfer tothe surroundings, the outlet temperature of the cold fluid in °C is:a)7.5b)32.5c)45.5d)70.0Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a counter flow heat exchanger, for the hot fluid the heat capacity = 2kJ/kg K, mass flow rate = 5 kg/s, inlet temperature = 150°C, outlet temperature = 100°C. For the cold fluid, heat capacity = 4 kJ/kg K, massflow rate = 10 kg/s, inlet temperature = 20°C. Neglecting heat transfer tothe surroundings, the outlet temperature of the cold fluid in °C is:a)7.5b)32.5c)45.5d)70.0Correct answer is option 'B'. Can you explain this answer?.
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