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Al is amphoteric metal and liberate hydrogen by reacting with both with dilute acids and bases . 2 moles of Al metal when reacted with either acid or base, the number of moles of dihydrogen liberated is ......
Correct answer is '3'. Can you explain this answer?
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Al is amphoteric metal and liberate hydrogen by reacting with both wit...
2 moles of Al = 6 equivalents Ai.Therefore hydrogen produced is also 6 equivalents i.e. 6g = 3 moles.
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Al is amphoteric metal and liberate hydrogen by reacting with both wit...
Al is an amphoteric metal, which means that it can react with both acids and bases. When Al reacts with acids or bases, it liberates hydrogen gas. In this case, we are given that 2 moles of Al metal reacts with either an acid or a base.
When Al reacts with an acid:
- The balanced chemical equation for the reaction is: 2Al + 6HCl → 2AlCl3 + 3H2
- From the equation, we can see that for every 2 moles of Al, 3 moles of dihydrogen (H2) are liberated.
- Therefore, when 2 moles of Al react with an acid, the number of moles of dihydrogen liberated is 3.
When Al reacts with a base:
- The balanced chemical equation for the reaction is: 2Al + 2NaOH + 6H2O → 2Na[Al(OH)4] + 3H2
- From the equation, we can see that for every 2 moles of Al, 3 moles of dihydrogen (H2) are liberated.
- Therefore, when 2 moles of Al react with a base, the number of moles of dihydrogen liberated is 3.
In both cases, the number of moles of dihydrogen liberated is the same, which is 3. This is because the stoichiometry of the reaction is such that for every 2 moles of Al, 3 moles of dihydrogen are produced.
In conclusion, when 2 moles of Al metal react with either an acid or a base, the number of moles of dihydrogen liberated is 3. This is due to the balanced chemical equations for the reactions, which show that for every 2 moles of Al, 3 moles of dihydrogen are produced.
When Al reacts with an acid:
- The balanced chemical equation for the reaction is: 2Al + 6HCl → 2AlCl3 + 3H2
- From the equation, we can see that for every 2 moles of Al, 3 moles of dihydrogen (H2) are liberated.
- Therefore, when 2 moles of Al react with an acid, the number of moles of dihydrogen liberated is 3.
When Al reacts with a base:
- The balanced chemical equation for the reaction is: 2Al + 2NaOH + 6H2O → 2Na[Al(OH)4] + 3H2
- From the equation, we can see that for every 2 moles of Al, 3 moles of dihydrogen (H2) are liberated.
- Therefore, when 2 moles of Al react with a base, the number of moles of dihydrogen liberated is 3.
In both cases, the number of moles of dihydrogen liberated is the same, which is 3. This is because the stoichiometry of the reaction is such that for every 2 moles of Al, 3 moles of dihydrogen are produced.
In conclusion, when 2 moles of Al metal react with either an acid or a base, the number of moles of dihydrogen liberated is 3. This is due to the balanced chemical equations for the reactions, which show that for every 2 moles of Al, 3 moles of dihydrogen are produced.
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Al is amphoteric metal and liberate hydrogen by reacting with both with dilute acids and bases . 2 moles of Al metal when reacted with either acid or base, the number of moles of dihydrogen liberated is ......Correct answer is '3'. Can you explain this answer?
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