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Q• Time t is equals to zero, car moving on a straight line has a velocity of 16m/s. It slows down with an acceleration of -0.5t m/s^2, where it is in second. Mark correct statement. A. the direction of velocity changes at t is equal to 8 second B. The distance travelled in 4 second is approximately 59 m. C. The distance travelled by the particle in 10 second is 94 m. D. The velocity at t = 10 second is 8 m/s.?
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Q• Time t is equals to zero, car moving on a straight line has a veloc...
Analysis:
Given:
Initial velocity (u) = 16 m/s
Acceleration (a) = -0.5t m/s^2
Time (t) = 0
To find:
A. The direction of velocity changes at t = 8 seconds
B. The distance traveled in 4 seconds
C. The distance traveled in 10 seconds
D. The velocity at t = 10 seconds
Solution:
1. The direction of velocity changes at t = 8 seconds
To determine if the direction of velocity changes, we need to find the time when the acceleration becomes zero. The acceleration is given by a = -0.5t.
Setting a = 0, we have:
0 = -0.5t
t = 0
Since the acceleration is zero at t = 0, it means the direction of velocity does not change at t = 8 seconds.
Therefore, statement A is false.
2. The distance traveled in 4 seconds
To find the distance traveled, we need to integrate the velocity function.
Given that the initial velocity (u) is 16 m/s:
v = u + at
v = 16 + (-0.5t)
v = 16 - 0.5t
Integrating v with respect to t, we get:
s = ∫(16 - 0.5t) dt
s = 16t - 0.25t^2 + C
To determine the constant of integration (C), we can use the initial condition when t = 0. At t = 0, the velocity is 16 m/s, so the initial position (s) is also zero:
0 = 16(0) - 0.25(0)^2 + C
C = 0
Substituting C back into the position equation, we have:
s = 16t - 0.25t^2
To find the distance traveled in 4 seconds, we evaluate s at t = 4:
s = 16(4) - 0.25(4)^2
s = 64 - 4
s = 60 m
Therefore, the distance traveled in 4 seconds is approximately 60 m.
3. The distance traveled by the particle in 10 seconds
Using the position equation derived earlier:
s = 16t - 0.25t^2
To find the distance traveled in 10 seconds, we evaluate s at t = 10:
s = 16(10) - 0.25(10)^2
s = 160 - 25
s = 135 m
Therefore, the distance traveled by the particle in 10 seconds is 135 m.
4. The velocity at t = 10 seconds
To find the velocity at t = 10 seconds, we substitute t = 10 into the velocity equation:
v = 16 - 0.5(10)
v = 16 - 5
v = 11 m/s
Therefore, the velocity at t = 10 seconds is 11 m/s.
Summary:
A. The direction of velocity changes at t = 8 seconds -
Given:
Initial velocity (u) = 16 m/s
Acceleration (a) = -0.5t m/s^2
Time (t) = 0
To find:
A. The direction of velocity changes at t = 8 seconds
B. The distance traveled in 4 seconds
C. The distance traveled in 10 seconds
D. The velocity at t = 10 seconds
Solution:
1. The direction of velocity changes at t = 8 seconds
To determine if the direction of velocity changes, we need to find the time when the acceleration becomes zero. The acceleration is given by a = -0.5t.
Setting a = 0, we have:
0 = -0.5t
t = 0
Since the acceleration is zero at t = 0, it means the direction of velocity does not change at t = 8 seconds.
Therefore, statement A is false.
2. The distance traveled in 4 seconds
To find the distance traveled, we need to integrate the velocity function.
Given that the initial velocity (u) is 16 m/s:
v = u + at
v = 16 + (-0.5t)
v = 16 - 0.5t
Integrating v with respect to t, we get:
s = ∫(16 - 0.5t) dt
s = 16t - 0.25t^2 + C
To determine the constant of integration (C), we can use the initial condition when t = 0. At t = 0, the velocity is 16 m/s, so the initial position (s) is also zero:
0 = 16(0) - 0.25(0)^2 + C
C = 0
Substituting C back into the position equation, we have:
s = 16t - 0.25t^2
To find the distance traveled in 4 seconds, we evaluate s at t = 4:
s = 16(4) - 0.25(4)^2
s = 64 - 4
s = 60 m
Therefore, the distance traveled in 4 seconds is approximately 60 m.
3. The distance traveled by the particle in 10 seconds
Using the position equation derived earlier:
s = 16t - 0.25t^2
To find the distance traveled in 10 seconds, we evaluate s at t = 10:
s = 16(10) - 0.25(10)^2
s = 160 - 25
s = 135 m
Therefore, the distance traveled by the particle in 10 seconds is 135 m.
4. The velocity at t = 10 seconds
To find the velocity at t = 10 seconds, we substitute t = 10 into the velocity equation:
v = 16 - 0.5(10)
v = 16 - 5
v = 11 m/s
Therefore, the velocity at t = 10 seconds is 11 m/s.
Summary:
A. The direction of velocity changes at t = 8 seconds -
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Q• Time t is equals to zero, car moving on a straight line has a velocity of 16m/s. It slows down with an acceleration of -0.5t m/s^2, where it is in second. Mark correct statement. A. the direction of velocity changes at t is equal to 8 second B. The distance travelled in 4 second is approximately 59 m. C. The distance travelled by the particle in 10 second is 94 m. D. The velocity at t = 10 second is 8 m/s.?
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Q• Time t is equals to zero, car moving on a straight line has a velocity of 16m/s. It slows down with an acceleration of -0.5t m/s^2, where it is in second. Mark correct statement. A. the direction of velocity changes at t is equal to 8 second B. The distance travelled in 4 second is approximately 59 m. C. The distance travelled by the particle in 10 second is 94 m. D. The velocity at t = 10 second is 8 m/s.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Q• Time t is equals to zero, car moving on a straight line has a velocity of 16m/s. It slows down with an acceleration of -0.5t m/s^2, where it is in second. Mark correct statement. A. the direction of velocity changes at t is equal to 8 second B. The distance travelled in 4 second is approximately 59 m. C. The distance travelled by the particle in 10 second is 94 m. D. The velocity at t = 10 second is 8 m/s.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q• Time t is equals to zero, car moving on a straight line has a velocity of 16m/s. It slows down with an acceleration of -0.5t m/s^2, where it is in second. Mark correct statement. A. the direction of velocity changes at t is equal to 8 second B. The distance travelled in 4 second is approximately 59 m. C. The distance travelled by the particle in 10 second is 94 m. D. The velocity at t = 10 second is 8 m/s.?.
Q• Time t is equals to zero, car moving on a straight line has a velocity of 16m/s. It slows down with an acceleration of -0.5t m/s^2, where it is in second. Mark correct statement. A. the direction of velocity changes at t is equal to 8 second B. The distance travelled in 4 second is approximately 59 m. C. The distance travelled by the particle in 10 second is 94 m. D. The velocity at t = 10 second is 8 m/s.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Q• Time t is equals to zero, car moving on a straight line has a velocity of 16m/s. It slows down with an acceleration of -0.5t m/s^2, where it is in second. Mark correct statement. A. the direction of velocity changes at t is equal to 8 second B. The distance travelled in 4 second is approximately 59 m. C. The distance travelled by the particle in 10 second is 94 m. D. The velocity at t = 10 second is 8 m/s.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q• Time t is equals to zero, car moving on a straight line has a velocity of 16m/s. It slows down with an acceleration of -0.5t m/s^2, where it is in second. Mark correct statement. A. the direction of velocity changes at t is equal to 8 second B. The distance travelled in 4 second is approximately 59 m. C. The distance travelled by the particle in 10 second is 94 m. D. The velocity at t = 10 second is 8 m/s.?.
Solutions for Q• Time t is equals to zero, car moving on a straight line has a velocity of 16m/s. It slows down with an acceleration of -0.5t m/s^2, where it is in second. Mark correct statement. A. the direction of velocity changes at t is equal to 8 second B. The distance travelled in 4 second is approximately 59 m. C. The distance travelled by the particle in 10 second is 94 m. D. The velocity at t = 10 second is 8 m/s.? in English & in Hindi are available as part of our courses for Class 11.
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Q• Time t is equals to zero, car moving on a straight line has a velocity of 16m/s. It slows down with an acceleration of -0.5t m/s^2, where it is in second. Mark correct statement. A. the direction of velocity changes at t is equal to 8 second B. The distance travelled in 4 second is approximately 59 m. C. The distance travelled by the particle in 10 second is 94 m. D. The velocity at t = 10 second is 8 m/s.?, a detailed solution for Q• Time t is equals to zero, car moving on a straight line has a velocity of 16m/s. It slows down with an acceleration of -0.5t m/s^2, where it is in second. Mark correct statement. A. the direction of velocity changes at t is equal to 8 second B. The distance travelled in 4 second is approximately 59 m. C. The distance travelled by the particle in 10 second is 94 m. D. The velocity at t = 10 second is 8 m/s.? has been provided alongside types of Q• Time t is equals to zero, car moving on a straight line has a velocity of 16m/s. It slows down with an acceleration of -0.5t m/s^2, where it is in second. Mark correct statement. A. the direction of velocity changes at t is equal to 8 second B. The distance travelled in 4 second is approximately 59 m. C. The distance travelled by the particle in 10 second is 94 m. D. The velocity at t = 10 second is 8 m/s.? theory, EduRev gives you an
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