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If the nitrogen atom had electronic configuration 1s7, it would have energy lower than that of the normal ground state configuration 1s2 2s2 2p3, because the electrons would be closer to the nucleus, yet 1s7 is not observed because it violates
  • a)
    Heisenberg uncertainty principle
  • b)
    Aufbau rule
  • c)
    Pauli exclusion principle 
  • d)
    Bohr postulate of stationary orbits
Correct answer is option 'C'. Can you explain this answer?
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If the nitrogen atom had electronic configuration 1s7, it would have e...
1s7 violate Pauli exclusion principle, according to which an orbital cannot have more than two electrons.
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If the nitrogen atom had electronic configuration 1s7, it would have e...
Understanding the Electronic Configuration of Nitrogen
The nitrogen atom's typical electronic configuration is 1s2 2s2 2p3. If it were to have an imaginary configuration of 1s7, it would not be observed due to fundamental principles of quantum mechanics.
What is the Pauli Exclusion Principle?
- The Pauli Exclusion Principle states that no two electrons in an atom can have the same set of four quantum numbers.
- Each electron in an atom occupies a unique quantum state.
Why 1s7 is Not Possible
- In the hypothetical 1s7 configuration:
- All seven electrons would occupy the same 1s orbital.
- This means they would share the same set of quantum numbers for the 1s orbital.
Consequences of Violating the Principle
- If 1s7 were to exist, it would violate the Pauli Exclusion Principle.
- This violation leads to an unstable configuration.
- Electrons cannot occupy the same state; thus, the configuration is not allowed.
Energy Considerations
- While it's true that electrons in a 1s orbital are closer to the nucleus and generally have lower energy:
- The violation of quantum mechanical principles makes such a configuration unviable.
- The normal ground state (1s2 2s2 2p3) remains stable and energetically favorable.
Conclusion
- The correct answer to why 1s7 is not observed is option C: the Pauli Exclusion Principle.
- This principle ensures that electron arrangements adhere to the fundamental rules of quantum mechanics, maintaining the stability of atomic structures.
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The French physicist Louis de-Broglie in 1924 postulated that matter, like radiation, should exhibit a dual behaviour. He proposed the following relationship between the wavelength of a material particle, its linear momentum p and planck constant h.The de Broglie relation implies that the wavelength of a particle should decreases as its velocity increases. It also implies that for a given velocity heavier particles should have shorter wavelength than lighter particles. The waves associated with particles in motion are called matter waves or de Broglie waves.These waves differ from the electromagnetic waves as they,(i) have lower velocities(ii) have no electrical and magnetic fields and(iii) are not emitted by the particle under consideration.The experimental confirmation of the deBroglie relation was obtained when Davisson and Germer, in 1927, observed that a beam of electrons is diffracted by a nickel crystal. As diffraction is a characteristic property of waves, hence the beam of electron behaves as a wave, as proposed by deBroglie.Werner Heisenberg considered the limits of how precisely we can measure properties of an electron or other microscopic particle like electron. He determined that there is a fundamental limit of how closely we can measure both position and momentum. The more accurately we measure the momentum of a particle, the less accurately we can determine its position. The converse is also ture. This is summed up in what we now call the Heisenberg uncertainty principle : It is impossible to determine simultaneously and precisely both the momentum and position of a particle. The product of undertainty in the position, x and the uncertainity in the momentum (mv) must be greater than or equal to h/4. i.e.Q. If the uncertainty in velocity position is same, then the uncertainty in momentum will be

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If the nitrogen atom had electronic configuration 1s7, it would have energy lower than that of the normal ground state configuration 1s22s22p3, because the electrons would be closer to the nucleus, yet 1s7is not observed because it violatesa)Heisenberg uncertainty principleb)Aufbau rulec)Pauli exclusion principled)Bohr postulate of stationary orbitsCorrect answer is option 'C'. Can you explain this answer?
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If the nitrogen atom had electronic configuration 1s7, it would have energy lower than that of the normal ground state configuration 1s22s22p3, because the electrons would be closer to the nucleus, yet 1s7is not observed because it violatesa)Heisenberg uncertainty principleb)Aufbau rulec)Pauli exclusion principled)Bohr postulate of stationary orbitsCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If the nitrogen atom had electronic configuration 1s7, it would have energy lower than that of the normal ground state configuration 1s22s22p3, because the electrons would be closer to the nucleus, yet 1s7is not observed because it violatesa)Heisenberg uncertainty principleb)Aufbau rulec)Pauli exclusion principled)Bohr postulate of stationary orbitsCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the nitrogen atom had electronic configuration 1s7, it would have energy lower than that of the normal ground state configuration 1s22s22p3, because the electrons would be closer to the nucleus, yet 1s7is not observed because it violatesa)Heisenberg uncertainty principleb)Aufbau rulec)Pauli exclusion principled)Bohr postulate of stationary orbitsCorrect answer is option 'C'. Can you explain this answer?.
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