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A student scored 36% marks in a exam and failed by 32 marks while another student scored 48% marks and passed by 64 marks. Find the pass percentage.
- a)30%
- b)35%
- c)40%
- d)33.33%
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A student scored 36% marks in a exam and failed by 32 marks while anot...
A student scored 36% marks in an exam and failed by 32 marks while another student scored 48% marks and passed by 64 marks;
∴The difference of 12% (= 48 - 36) creates the difference of marks equal to 96 (= 64 + 32);
∴ 0.12 × Maximum marks = 96
⇒ Maximum marks = 96/0.12 = 800
∴ Pass marks = 800 × 0.36 + 32 = 320
∴ Pass percentage = [320/800] × 100 = 40%
∴The difference of 12% (= 48 - 36) creates the difference of marks equal to 96 (= 64 + 32);
∴ 0.12 × Maximum marks = 96
⇒ Maximum marks = 96/0.12 = 800
∴ Pass marks = 800 × 0.36 + 32 = 320
∴ Pass percentage = [320/800] × 100 = 40%
Most Upvoted Answer
A student scored 36% marks in a exam and failed by 32 marks while anot...
Given:
Student A scored 36% marks and failed by 32 marks
Student B scored 48% marks and passed by 64 marks
To Find: Pass percentage
Solution:
Let us assume the maximum marks of the exam to be "x".
From the given data,
Student A scored 36% marks and failed by 32 marks
⇒ Student A scored (36/100)x marks
⇒ (36/100)x = (Total marks - 32)
Student B scored 48% marks and passed by 64 marks
⇒ Student B scored (48/100)x marks
⇒ (48/100)x = (Total marks + 64)
Now, let us solve for "x"
(36/100)x + 32 = (48/100)x - 64
⇒ 12x = 960
⇒ x = 80
Therefore, the maximum marks of the exam were 80.
Now, let us find the pass percentage.
Pass Percentage = (Marks scored by student B / Maximum marks) × 100
= (48/100) × 80
= 38.4%
Therefore, the pass percentage is 38.4%, which is closest to option C (40%).
Student A scored 36% marks and failed by 32 marks
Student B scored 48% marks and passed by 64 marks
To Find: Pass percentage
Solution:
Let us assume the maximum marks of the exam to be "x".
From the given data,
Student A scored 36% marks and failed by 32 marks
⇒ Student A scored (36/100)x marks
⇒ (36/100)x = (Total marks - 32)
Student B scored 48% marks and passed by 64 marks
⇒ Student B scored (48/100)x marks
⇒ (48/100)x = (Total marks + 64)
Now, let us solve for "x"
(36/100)x + 32 = (48/100)x - 64
⇒ 12x = 960
⇒ x = 80
Therefore, the maximum marks of the exam were 80.
Now, let us find the pass percentage.
Pass Percentage = (Marks scored by student B / Maximum marks) × 100
= (48/100) × 80
= 38.4%
Therefore, the pass percentage is 38.4%, which is closest to option C (40%).
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A student scored 36% marks in a exam and failed by 32 marks while another student scored 48% marks and passed by 64 marks. Find the pass percentage.a)30%b)35%c)40%d)33.33%Correct answer is option 'C'. Can you explain this answer?
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