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In a vapour compression refrigeration plant, the refrigerant leaves the evaporator at 195 kJ/kg and the condenser at 65 kJ/kg. For 1 kg/s of refrigerant, what is the refrigeration effect?
  • a)
    70 KW  
  • b)
    100 KW  
  • c)
    130 KW  
  • d)
    160 KW 
Correct answer is option 'C'. Can you explain this answer?
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Given:
- Refrigerant leaves the evaporator at 195 kJ/kg
- Refrigerant leaves the condenser at 65 kJ/kg
- Mass flow rate of refrigerant = 1 kg/s

To find:
Refrigeration effect

Assumptions:
- The refrigeration cycle is operating on a steady-state basis.
- There are no heat losses or gains in the system.

Formula:
Refrigeration effect (Q) = h1 - h2

Explanation:
The refrigeration effect is the amount of heat energy removed from the refrigerated space by the refrigeration system per unit time. It is given by the difference in enthalpy between the refrigerant at the evaporator inlet and the refrigerant at the condenser outlet.

Using the given values:
- h1 = 195 kJ/kg (enthalpy at evaporator exit)
- h2 = 65 kJ/kg (enthalpy at condenser exit)

Substituting these values in the formula:
Refrigeration effect (Q) = 195 kJ/kg - 65 kJ/kg = 130 kJ/kg

Since the mass flow rate of the refrigerant is given as 1 kg/s, the refrigeration effect can be calculated as:
Refrigeration effect (Q) = 130 kJ/kg * 1 kg/s = 130 kW

Conclusion:
Therefore, the refrigeration effect for 1 kg/s of refrigerant is 130 kW. Hence, the correct answer is option C) 130 KW.
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In a vapour compression refrigeration plant, the refrigerant leaves the evaporator at 195 kJ/kg and the condenser at 65 kJ/kg. For 1 kg/s of refrigerant, what is the refrigeration effect?a)70 KW b)100 KW c)130 KW d)160 KWCorrect answer is option 'C'. Can you explain this answer?
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