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10 mm diameter holes are to be punched in a steel sheet of 3 mm thickness. Shear strength of the material is 400 N / mm2 and penetration is 40%. Shear provided on the punch is 2 mm.The blanking force during the operation will be
- a)22.6 kN
- b)37.7 kN
- c)61.6 kN
- d)94.3 kN
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
10 mm diameter holes are to be punched in a steel sheet of 3 mm thickn...
The blanking force (P) = 
= π x 10 x 3 x 400 x 
= 22 .62kN
= π x 10 x 3 x 400 x = 22 .62kNMost Upvoted Answer
10 mm diameter holes are to be punched in a steel sheet of 3 mm thickn...
Blanking is a shearing process used to cut sheet metal into desired shapes. In this process, a punch is used to create a hole in the material, while a die is used to support the material and provide a clean cut. The force required for blanking can be calculated using the shear strength and the area of the punched hole.
Given data:
- Diameter of the hole (d): 10 mm
- Thickness of the sheet (t): 3 mm
- Shear strength of the material (σ): 400 N/mm2
- Penetration (P): 40% (This represents the percentage of the sheet thickness that is cut through during blanking)
- Shear provided on the punch (s): 2 mm
Calculations:
1. Area of the punched hole:
The area of a circle is given by the formula A = πr^2, where r is the radius.
Since the diameter is given, the radius can be calculated as r = d/2.
Substituting the values, A = π(10/2)^2 = 78.54 mm^2.
2. Effective thickness of the sheet:
The effective thickness is calculated by subtracting the shear provided on the punch from the actual thickness of the sheet.
t' = t - s = 3 mm - 2 mm = 1 mm.
3. Shear force required:
The shear force required can be calculated using the formula F = A * σ * P * t'.
Substituting the values, F = 78.54 mm^2 * 400 N/mm^2 * 0.4 * 1 mm = 12,566.4 N = 12.57 kN.
Therefore, the blanking force required during the operation is approximately 12.57 kN.
The correct answer is option 'A' (22.6 kN). It seems there may be an error in the given answer, as the calculated force is different from the provided options.
Given data:
- Diameter of the hole (d): 10 mm
- Thickness of the sheet (t): 3 mm
- Shear strength of the material (σ): 400 N/mm2
- Penetration (P): 40% (This represents the percentage of the sheet thickness that is cut through during blanking)
- Shear provided on the punch (s): 2 mm
Calculations:
1. Area of the punched hole:
The area of a circle is given by the formula A = πr^2, where r is the radius.
Since the diameter is given, the radius can be calculated as r = d/2.
Substituting the values, A = π(10/2)^2 = 78.54 mm^2.
2. Effective thickness of the sheet:
The effective thickness is calculated by subtracting the shear provided on the punch from the actual thickness of the sheet.
t' = t - s = 3 mm - 2 mm = 1 mm.
3. Shear force required:
The shear force required can be calculated using the formula F = A * σ * P * t'.
Substituting the values, F = 78.54 mm^2 * 400 N/mm^2 * 0.4 * 1 mm = 12,566.4 N = 12.57 kN.
Therefore, the blanking force required during the operation is approximately 12.57 kN.
The correct answer is option 'A' (22.6 kN). It seems there may be an error in the given answer, as the calculated force is different from the provided options.
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