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In a right angled triangle the hypotenuse is 2√2 times the perpendicular drawn from the opposite vertex. Then the other acute angles of the triangle are
  • a)
     
  • b)
  • c)
     
  • d)
     
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In a right angled triangle the hypotenuse is 2√2times the perpen...
AC = x/(sin∠ACD) = x/sinC
AB = x/sinB
x2(1/sin2C + 1/sin2B) = 8x2
sin2B + sin2C = 8sin2C sin2B

1 = 8sin2C cos2C
(sin2C) = 1/√2 ⇒ C = π/8 ⇒ B = 3π/8
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In a right angled triangle the hypotenuse is 2√2times the perpen...
B
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In a right angled triangle the hypotenuse is 2√2times the perpendicular drawn from the opposite vertex. Then the other acute angles of the triangle area)b)c)d)Correct answer is option 'B'. Can you explain this answer?
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