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Two numbers are in ratio 7 : 11. If 7 is added to each of the numbers, the ratio becomes 2 : 3. The smaller number is
  • a)
    39
  • b)
    49
  • c)
    66
  • d)
    77
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Two numbers are in ratio 7 : 11. If 7 is added to each of the numbers,...
49 
Let numbers are 7x and 11x.
According to question,
(7x+7)/(11x+7)=2/3;
Or, 22x+14=21x+21;
Or, x=7;
Smaller number = 7 × 7 = 49. 
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Most Upvoted Answer
Two numbers are in ratio 7 : 11. If 7 is added to each of the numbers,...
To solve this problem, we can use the concept of ratios and algebraic equations.

Given:
The ratio of two numbers is 7:11.
When 7 is added to each number, the ratio becomes 2:3.

Let's assume the two numbers are 7x and 11x, where x is a common factor.

Equation 1: 7x : 11x
Equation 2: (7x + 7) : (11x + 7) = 2 : 3

To find the value of x, we can equate the two ratios and solve for x.

Equating the two ratios:
(7x + 7) / (11x + 7) = 2 / 3

Cross multiplying:
3(7x + 7) = 2(11x + 7)

Expanding:
21x + 21 = 22x + 14

Simplifying:
21x - 22x = 14 - 21
-x = -7
x = 7

Now that we have the value of x, we can find the two numbers.

The smaller number = 7x = 7 * 7 = 49

Therefore, the smaller number is 49, which corresponds to option B.
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Two numbers are in ratio 7 : 11. If 7 is added to each of the numbers, the ratio becomes 2 : 3. The smaller number isa)39b)49c)66d)77Correct answer is option 'B'. Can you explain this answer?
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