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There are four complexes of Ni. Select the complex(es) which will be attracted by magnetic field.
I. [Ni(CN)4]2- II.[NiCl4]2- III.Ni(CO)4 IV. [Ni(H2O)6]2+
- a)Only I
- b)Only II
- c)I, II and IV
- d)II and IV
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
There are four complexes of Ni. Select the complex(es) which will be a...
Diamagnetic complexes are [Ni(CN)4]2- and Ni(CO)4.
Paramagnetic complexes are
[NiCI4]2- and [Ni(H2O)6]2+ (attracted)
Paramagnetic complexes are
[NiCI4]2- and [Ni(H2O)6]2+ (attracted)
Most Upvoted Answer
There are four complexes of Ni. Select the complex(es) which will be a...
The magnetic properties of a complex depend on the presence of unpaired electrons. If a complex has unpaired electrons, it will be attracted by a magnetic field. Let's analyze each complex individually to determine which ones have unpaired electrons and will be attracted by a magnetic field.
I. [Ni(CN)4]2-
This complex has a coordination number of 4, meaning that it forms four bonds with the central Ni atom. The cyanide ligands (CN-) are strong-field ligands that cause pairing of the electrons in the 3d orbitals of Ni. As a result, this complex does not have any unpaired electrons and will not be attracted by a magnetic field.
II. [NiCl4]2-
Similar to the first complex, this complex also has a coordination number of 4. The chloride ligands (Cl-) are weak-field ligands that do not cause significant pairing of the electrons in the 3d orbitals of Ni. Therefore, this complex has unpaired electrons and will be attracted by a magnetic field.
III. Ni(CO)4
This complex has a coordination number of 4 and consists of four carbon monoxide (CO) ligands. CO is a strong-field ligand that causes pairing of the electrons in the 3d orbitals of Ni. Consequently, this complex does not have any unpaired electrons and will not be attracted by a magnetic field.
IV. [Ni(H2O)6]2
This complex has a coordination number of 6 and consists of six water (H2O) ligands. Water is a weak-field ligand that does not cause significant pairing of the electrons in the 3d orbitals of Ni. Therefore, this complex has unpaired electrons and will be attracted by a magnetic field.
Based on the analysis above, complexes II and IV have unpaired electrons and will be attracted by a magnetic field. Hence, the correct answer is option 'D' - II and IV.
I. [Ni(CN)4]2-
This complex has a coordination number of 4, meaning that it forms four bonds with the central Ni atom. The cyanide ligands (CN-) are strong-field ligands that cause pairing of the electrons in the 3d orbitals of Ni. As a result, this complex does not have any unpaired electrons and will not be attracted by a magnetic field.
II. [NiCl4]2-
Similar to the first complex, this complex also has a coordination number of 4. The chloride ligands (Cl-) are weak-field ligands that do not cause significant pairing of the electrons in the 3d orbitals of Ni. Therefore, this complex has unpaired electrons and will be attracted by a magnetic field.
III. Ni(CO)4
This complex has a coordination number of 4 and consists of four carbon monoxide (CO) ligands. CO is a strong-field ligand that causes pairing of the electrons in the 3d orbitals of Ni. Consequently, this complex does not have any unpaired electrons and will not be attracted by a magnetic field.
IV. [Ni(H2O)6]2
This complex has a coordination number of 6 and consists of six water (H2O) ligands. Water is a weak-field ligand that does not cause significant pairing of the electrons in the 3d orbitals of Ni. Therefore, this complex has unpaired electrons and will be attracted by a magnetic field.
Based on the analysis above, complexes II and IV have unpaired electrons and will be attracted by a magnetic field. Hence, the correct answer is option 'D' - II and IV.
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There are four complexes of Ni. Select the complex(es) which will be attracted by magnetic field.I.[Ni(CN)4]2- II.[NiCl4]2- III.Ni(CO)4IV.[Ni(H2O)6]2+a)Only Ib)Only IIc)I, II and IVd)II and IVCorrect answer is option 'D'. Can you explain this answer?
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There are four complexes of Ni. Select the complex(es) which will be attracted by magnetic field.I.[Ni(CN)4]2- II.[NiCl4]2- III.Ni(CO)4IV.[Ni(H2O)6]2+a)Only Ib)Only IIc)I, II and IVd)II and IVCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about There are four complexes of Ni. Select the complex(es) which will be attracted by magnetic field.I.[Ni(CN)4]2- II.[NiCl4]2- III.Ni(CO)4IV.[Ni(H2O)6]2+a)Only Ib)Only IIc)I, II and IVd)II and IVCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There are four complexes of Ni. Select the complex(es) which will be attracted by magnetic field.I.[Ni(CN)4]2- II.[NiCl4]2- III.Ni(CO)4IV.[Ni(H2O)6]2+a)Only Ib)Only IIc)I, II and IVd)II and IVCorrect answer is option 'D'. Can you explain this answer?.
There are four complexes of Ni. Select the complex(es) which will be attracted by magnetic field.I.[Ni(CN)4]2- II.[NiCl4]2- III.Ni(CO)4IV.[Ni(H2O)6]2+a)Only Ib)Only IIc)I, II and IVd)II and IVCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about There are four complexes of Ni. Select the complex(es) which will be attracted by magnetic field.I.[Ni(CN)4]2- II.[NiCl4]2- III.Ni(CO)4IV.[Ni(H2O)6]2+a)Only Ib)Only IIc)I, II and IVd)II and IVCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There are four complexes of Ni. Select the complex(es) which will be attracted by magnetic field.I.[Ni(CN)4]2- II.[NiCl4]2- III.Ni(CO)4IV.[Ni(H2O)6]2+a)Only Ib)Only IIc)I, II and IVd)II and IVCorrect answer is option 'D'. Can you explain this answer?.
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