In the following question, select the odd letters/numbers from the giv...
Here, in all groups consider the numerical value of each letter and take the second letter to be opposite the first letter.
The number is the sum of numerical value of second letter and twice of the first letter.
1) KP29 → K = 11, Opposite of K = P (16), Number = 2 × 11 + 16 = 22 + 16 = 38 ≠ 29
2) FU33 → F = 6, Opposite of F = U (21), Number = 2 × 6 + 21 = 12 + 21 = 33
3) CX30 → C = 3, Opposite of C = X (24), Number = 2 × 3 + 24 = 6 + 24 = 30
4) JQ37 → J = 10, Opposite of J = Q (17), Number = 2 × 10 + 17 = 20 + 17 = 37
Hence, the correct answer is KP29.
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In the following question, select the odd letters/numbers from the giv...
Odd Letters/Numbers in Given Alternatives
Introduction:
This question belongs to the Defence category and requires the selection of odd letters/numbers from the given alternatives. Let's solve the question step by step.
Analysis:
a) KP29
b) FU33
c) CX30
d) JQ37
To solve this question, we need to compare the given alternatives and find out the odd one. Let's compare each alternative one by one.
a) KP29
Here, K and P are odd letters, and 29 is an even number. Hence, this alternative is odd.
b) FU33
Here, F and U are even letters, and 33 is an odd number. Hence, this alternative is not odd.
c) CX30
Here, C and X are even letters, and 30 is an even number. Hence, this alternative is not odd.
d) JQ37
Here, J and Q are odd letters, and 37 is an odd number. Hence, this alternative is not odd.
Conclusion:
From the above analysis, we can conclude that the odd letters/numbers from the given alternatives are present in option 'A', i.e., KP29. Therefore, the correct answer to this question is option 'A'.
In the following question, select the odd letters/numbers from the giv...
KP29