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The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is :
  • a)
    74
  • b)
    94
  • c)
    184
  • d)
    364
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The least multiple of 7, which leaves a remainder of 4, when divided b...
L.C.M. of 6, 9, 15 and 18 is 90.
Let required number be 90k + 4, which is multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4.
Required number = (90 × 4) + 4 = 364.
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Most Upvoted Answer
The least multiple of 7, which leaves a remainder of 4, when divided b...

Finding the Least Multiple:

To find the least multiple of 7 that leaves a remainder of 4 when divided by 6, 9, 15, and 18, we need to consider the LCM of 6, 9, 15, and 18.
We find the LCM of these numbers which is 90.

Finding the Number:

When a number leaves a remainder of 4 when divided by 6, 9, 15, and 18, it means the number is of the form 90k + 4, where k is an integer.

Checking the Options:

1. 74 is not a multiple of 7, so it cannot be the answer.
2. 94 is not a multiple of 7, so it cannot be the answer.
3. 184 is not a multiple of 7, so it cannot be the answer.
4. 364 is a multiple of 7 and when divided by 6, 9, 15, and 18, it leaves a remainder of 4. Hence, the correct answer is option D.

Therefore, the least multiple of 7 that leaves a remainder of 4 when divided by 6, 9, 15, and 18 is 364.
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The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is :a)74b)94c)184d)364Correct answer is option 'D'. Can you explain this answer?
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