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The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is :

  • a)
    101

  • b)
    107

  • c)
    111

  • d)
    185

Correct answer is option 'C'. Can you explain this answer?
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The product of two numbers is 4107. If the H.C.F. of these numbers is ...

Given Information:
- Product of two numbers = 4107
- H.C.F. of the two numbers = 37

Approach:
To find the greater number, we need to find the two numbers first using the product and H.C.F. given.

Calculation:
Let the two numbers be a and b.
Given that the product of the two numbers is 4107, we have:
a * b = 4107

Given that the H.C.F. of the two numbers is 37, we can express the numbers as:
a = 37x
b = 37y

Substitute the values of a and b in the equation a * b = 4107:
37x * 37y = 4107
1379xy = 4107
xy = 4107 / 1379
xy = 3

Since x and y are factors of 3, the possible combinations are (1, 3) and (3, 1).

Therefore, the two numbers are:
a = 37 * 1 = 37
b = 37 * 3 = 111

Hence, the greater number is 111, which is option 'C'.
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The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is :a)101b)107c)111d)185Correct answer is option 'C'. Can you explain this answer?
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