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A complex compound is represented as CoCl3. xNH3. Its 0.1 M solution in water shows depression in freezing point equal to 0.0558K. Assuming 100% ionisation of complex and coordination number of Co to be six, calculate the value of x. Kf for H2O is 1.86 K kgmol–1.
  • a)
    a
  • b)
    b
  • c)
    c
  • d)
    d
Correct answer is '5'. Can you explain this answer?
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A complex compound is represented as CoCl3. xNH3. Its 0.1 M solution i...
To find the value of x, we need to use the formula for depression in freezing point:

ΔTf = i * Kf * m

Where:
ΔTf = depression in freezing point
i = van't Hoff factor (number of particles into which the compound dissociates)
Kf = freezing point depression constant for the solvent (water)
m = molality of the solution (moles of solute per kilogram of solvent)

Given:
ΔTf = 0.0558 K
Kf for H2O = 1.86 K kgmol

To find i, we need to know the number of particles into which the complex dissociates. Since the coordination number of Co is six, there are six NH3 molecules associated with the complex. Therefore, i = 7 (CoCl3 + 6NH3).

Next, we need to find the molality of the solution. Molality is defined as moles of solute per kilogram of solvent. In this case, the solute is the complex CoCl3.xNH3. Let's assume the mass of the solvent is 1 kg.

Molar mass of CoCl3 = (1 * 58.93) + (3 * 35.45) = 58.93 + 106.35 = 165.28 g/mol

0.1 M solution means 0.1 moles of complex in 1 liter of solution.
Therefore, moles of complex in 1 kg of solvent = (0.1 moles / 1000 g) * 1000 g = 0.1 moles

Now, we can calculate the molality:

molality (m) = moles of solute / mass of solvent (in kg)
m = 0.1 moles / 1 kg = 0.1 mol/kg

Now, we can substitute the values into the equation:

0.0558 K = 7 * 1.86 K kgmol * 0.1 mol/kg

Simplifying:

0.0558 K = 12.282 K kgmol/mol

Dividing both sides by 12.282 K kgmol/mol:

x = 0.0558 K / 12.282 K kgmol/mol = 0.0045

Therefore, the value of x is approximately 0.0045.
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A complex compound is represented as CoCl3. xNH3. Its 0.1 M solution in water shows depression in freezing point equal to 0.0558K. Assuming 100% ionisation of complex and coordination number of Co to be six, calculate the value of x. Kffor H2O is 1.86 K kgmol–1.a)ab)bc)cd)dCorrect answer is '5'. Can you explain this answer?
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A complex compound is represented as CoCl3. xNH3. Its 0.1 M solution in water shows depression in freezing point equal to 0.0558K. Assuming 100% ionisation of complex and coordination number of Co to be six, calculate the value of x. Kffor H2O is 1.86 K kgmol–1.a)ab)bc)cd)dCorrect answer is '5'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A complex compound is represented as CoCl3. xNH3. Its 0.1 M solution in water shows depression in freezing point equal to 0.0558K. Assuming 100% ionisation of complex and coordination number of Co to be six, calculate the value of x. Kffor H2O is 1.86 K kgmol–1.a)ab)bc)cd)dCorrect answer is '5'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A complex compound is represented as CoCl3. xNH3. Its 0.1 M solution in water shows depression in freezing point equal to 0.0558K. Assuming 100% ionisation of complex and coordination number of Co to be six, calculate the value of x. Kffor H2O is 1.86 K kgmol–1.a)ab)bc)cd)dCorrect answer is '5'. Can you explain this answer?.
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