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A cell has an emf 1.5 V. When connected across an external resistance of 2 Ω, the terminal potential difference falls to 1.0 V. The internal resistance of the cell is 
  • a)
    2Ω 
  • b)
    1.5 Ω
  • c)
    1.0 Ω
  • d)
    0.5 Ω
Correct answer is option 'C'. Can you explain this answer?
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A cell has an emf 1.5 V. When connected across an external resistance ...
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A cell has an emf 1.5 V. When connected across an external resistance ...
Ω, the current flowing through the cell is 0.75 A.

We can use Ohm's law to calculate the internal resistance of the cell:

V = IR + emf

where V is the voltage across the external resistance, I is the current flowing through the circuit, R is the resistance of the external resistor, and emf is the electromotive force of the cell.

Plugging in the values we have:

2 = 0.75 x R + 1.5

Solving for R:

R = (2 - 1.5) / 0.75

R = 0.67 Ω

Therefore, the internal resistance of the cell is 0.67 Ω.
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A cell has an emf 1.5 V. When connected across an external resistance of 2 Ω, the terminal potential difference falls to 1.0 V. The internal resistance of the cell isa)2Ωb)1.5 Ωc)1.0 Ωd)0.5 ΩCorrect answer is option 'C'. Can you explain this answer?
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A cell has an emf 1.5 V. When connected across an external resistance of 2 Ω, the terminal potential difference falls to 1.0 V. The internal resistance of the cell isa)2Ωb)1.5 Ωc)1.0 Ωd)0.5 ΩCorrect answer is option 'C'. Can you explain this answer? for Defence 2024 is part of Defence preparation. The Question and answers have been prepared according to the Defence exam syllabus. Information about A cell has an emf 1.5 V. When connected across an external resistance of 2 Ω, the terminal potential difference falls to 1.0 V. The internal resistance of the cell isa)2Ωb)1.5 Ωc)1.0 Ωd)0.5 ΩCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Defence 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cell has an emf 1.5 V. When connected across an external resistance of 2 Ω, the terminal potential difference falls to 1.0 V. The internal resistance of the cell isa)2Ωb)1.5 Ωc)1.0 Ωd)0.5 ΩCorrect answer is option 'C'. Can you explain this answer?.
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