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Consider the region defined by |x|,|y| and |z| < 1. Let ε = 5ε0 , μ = 4μo  and σ = 0 the displacement current densityJd  = 20cos(1.5 x 108 t - ax)uy μA/m2. Assume no DC fields are present.
  • a)
    6sin (1.5 x 108 t - ax) uy mV/m
  • b)
    6cos (1.5 x 108 t - ax) uy mV/m
  • c)
    3cos (1.5 x 108 t - ax) uy mV/m
  • d)
    3sin (1.5 x 108 t - ax) uy mV/m
Correct answer is option 'D'. Can you explain this answer?
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Consider the region defined by |x|,|y| and |z| < 1. Let ε = 5...
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Consider the region defined by |x|,|y| and |z| < 1. Let ε = 5...


Explanation:

Displacement Current Density (Jd) Formula:
- Jd = ε * ∂E/∂t

Given values:
- ε = 50
- a = 40
- Jd = 20cos(1.5 x 10^8t - ax) uy A/m^2

Calculating the Electric Field (E):
- Jd = ε * ∂E/∂t
- ∂E/∂t = Jd / ε
- ∂E/∂t = (20cos(1.5 x 10^8t - 40x) uy) / 50
- ∂E/∂t = 0.4cos(1.5 x 10^8t - 40x) uy

Calculating the Voltage (V):
- E = -∇V
- V = -∫E.dx
- V = -∫(-0.4cos(1.5 x 10^8t - 40x) uy).dx
- V = 0.4sin(1.5 x 10^8t - 40x) uy

Converting Voltage to mV/m:
- V = 0.4sin(1.5 x 10^8t - 40x) uy V/m
- V = 400sin(1.5 x 10^8t - 40x) uy mV/m

Therefore, the correct answer is option 'd) 3sin(1.5 x 10^8t - 40x) uy mV/m'.
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Consider the region defined by |x|,|y| and |z| < 1. Let ε = 5ε0,μ = 4μoand σ = 0 the displacement current densityJd= 20cos(1.5 x 108t - ax)uyμA/m2. Assume no DC fields are present.a)6sin (1.5 x 108t - ax) uy mV/mb)6cos(1.5 x 108t - ax) uy mV/mc)3cos (1.5 x 108t - ax) uy mV/md)3sin (1.5 x 108t - ax) uy mV/mCorrect answer is option 'D'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2026 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Consider the region defined by |x|,|y| and |z| < 1. Let ε = 5ε0,μ = 4μoand σ = 0 the displacement current densityJd= 20cos(1.5 x 108t - ax)uyμA/m2. Assume no DC fields are present.a)6sin (1.5 x 108t - ax) uy mV/mb)6cos(1.5 x 108t - ax) uy mV/mc)3cos (1.5 x 108t - ax) uy mV/md)3sin (1.5 x 108t - ax) uy mV/mCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the region defined by |x|,|y| and |z| < 1. Let ε = 5ε0,μ = 4μoand σ = 0 the displacement current densityJd= 20cos(1.5 x 108t - ax)uyμA/m2. Assume no DC fields are present.a)6sin (1.5 x 108t - ax) uy mV/mb)6cos(1.5 x 108t - ax) uy mV/mc)3cos (1.5 x 108t - ax) uy mV/md)3sin (1.5 x 108t - ax) uy mV/mCorrect answer is option 'D'. Can you explain this answer?.
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