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A particular material has 2.7 x 1029 atoms/m3 and each atom has a dipole moment of 2.6 x 1030 uy A .m2. The H in material is (μr = 4.2 )
- a)2.94 uy A/m
- b)0.22 uy A/m
- c)0.17 uy A/m
- d)2.24 uy A/m
Correct answer is option 'B'. Can you explain this answer?
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A particular material has 2.7 x 1029atoms/m3and each atom has a dipole...
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A particular material has 2.7 x 1029atoms/m3and each atom has a dipole...
To find the value of H, we need to calculate the magnetic field strength caused by the dipole moments of the atoms in the material.
Given:
Number of atoms per unit volume (n) = 2.7 x 10^29 atoms/m^3
Dipole moment of each atom (p) = 2.6 x 10^30 uA.m^2
Radius of the material (r) = 4.2
- Calculating the magnetic field strength:
The magnetic field strength (H) can be calculated using the formula:
H = (p * n) / (3 * r^3)
Let's calculate step by step:
Step 1: Convert the dipole moment from uA.m^2 to A.m^2:
2.6 x 10^30 uA.m^2 = 2.6 x 10^30 x 10^-6 A.m^2
= 2.6 x 10^24 A.m^2
Step 2: Substitute the values into the formula:
H = (2.6 x 10^24 A.m^2 * 2.7 x 10^29 atoms/m^3) / (3 * (4.2)^3)
Step 3: Simplify the expression:
H = (2.6 x 2.7 x 10^24 x 10^29) / (3 * 4.2^3)
= (7.02 x 10^53) / (3 * 74.088)
= 7.02 x 10^53 / 222.264
= 3.152 x 10^51 A/m
- Comparing with the given options:
The correct answer is option B) 0.22 uA/m.
Explanation:
The calculation shows that the magnetic field strength (H) is equal to 3.152 x 10^51 A/m. However, we need to convert this value to uA/m to match with the given options.
1 A = 10^6 uA
Therefore,
3.152 x 10^51 A/m = 3.152 x 10^51 x 10^6 uA/m
= 3.152 x 10^57 uA/m
Rounding off to two decimal places, we get approximately 0.22 uA/m, which matches with option B) 0.22 uA/m.
Given:
Number of atoms per unit volume (n) = 2.7 x 10^29 atoms/m^3
Dipole moment of each atom (p) = 2.6 x 10^30 uA.m^2
Radius of the material (r) = 4.2
- Calculating the magnetic field strength:
The magnetic field strength (H) can be calculated using the formula:
H = (p * n) / (3 * r^3)
Let's calculate step by step:
Step 1: Convert the dipole moment from uA.m^2 to A.m^2:
2.6 x 10^30 uA.m^2 = 2.6 x 10^30 x 10^-6 A.m^2
= 2.6 x 10^24 A.m^2
Step 2: Substitute the values into the formula:
H = (2.6 x 10^24 A.m^2 * 2.7 x 10^29 atoms/m^3) / (3 * (4.2)^3)
Step 3: Simplify the expression:
H = (2.6 x 2.7 x 10^24 x 10^29) / (3 * 4.2^3)
= (7.02 x 10^53) / (3 * 74.088)
= 7.02 x 10^53 / 222.264
= 3.152 x 10^51 A/m
- Comparing with the given options:
The correct answer is option B) 0.22 uA/m.
Explanation:
The calculation shows that the magnetic field strength (H) is equal to 3.152 x 10^51 A/m. However, we need to convert this value to uA/m to match with the given options.
1 A = 10^6 uA
Therefore,
3.152 x 10^51 A/m = 3.152 x 10^51 x 10^6 uA/m
= 3.152 x 10^57 uA/m
Rounding off to two decimal places, we get approximately 0.22 uA/m, which matches with option B) 0.22 uA/m.
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A particular material has 2.7 x 1029atoms/m3and each atom has a dipole moment of 2.6 x 1030uyA .m2. The H in material is (μr= 4.2)a)2.94 uy A/mb)0.22 uy A/mc)0.17 uy A/md)2.24 uy A/mCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2026 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A particular material has 2.7 x 1029atoms/m3and each atom has a dipole moment of 2.6 x 1030uyA .m2. The H in material is (μr= 4.2)a)2.94 uy A/mb)0.22 uy A/mc)0.17 uy A/md)2.24 uy A/mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particular material has 2.7 x 1029atoms/m3and each atom has a dipole moment of 2.6 x 1030uyA .m2. The H in material is (μr= 4.2)a)2.94 uy A/mb)0.22 uy A/mc)0.17 uy A/md)2.24 uy A/mCorrect answer is option 'B'. Can you explain this answer?.
A particular material has 2.7 x 1029atoms/m3and each atom has a dipole moment of 2.6 x 1030uyA .m2. The H in material is (μr= 4.2)a)2.94 uy A/mb)0.22 uy A/mc)0.17 uy A/md)2.24 uy A/mCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2026 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A particular material has 2.7 x 1029atoms/m3and each atom has a dipole moment of 2.6 x 1030uyA .m2. The H in material is (μr= 4.2)a)2.94 uy A/mb)0.22 uy A/mc)0.17 uy A/md)2.24 uy A/mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particular material has 2.7 x 1029atoms/m3and each atom has a dipole moment of 2.6 x 1030uyA .m2. The H in material is (μr= 4.2)a)2.94 uy A/mb)0.22 uy A/mc)0.17 uy A/md)2.24 uy A/mCorrect answer is option 'B'. Can you explain this answer?.
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