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A metal complex having the composition Cr(NH3)4CI2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in cone, ammonia.
Q.
The isomerism shown by complex A is
- a)ionisation
- b)geometrical
- c)linkage
- d)Both (a) and (b)
Correct answer is option 'D'. Can you explain this answer?
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A metal complex having the composition Cr(NH3)4CI2Br has been isolated...
Ionisation isomers [Cr(NH3)4CIBr]CI and [Cr(NH3)4CI2]Br
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A metal complex having the composition Cr(NH3)4CI2Br has been isolated...
Isomerism in Complex A:
The complex A, Cr(NH3)4CI2Br, shows both ionization isomerism and geometrical isomerism.
Ionization Isomerism:
Ionization isomerism occurs when there is a difference in the way ligands are bonded to the metal center. In this case, Cr(NH3)4CI2Br can be written as [Cr(NH3)4CI]+[Br]- or [Cr(NH3)4Br]+[CI]-. The chloride and bromide ions can exchange places with each other, resulting in two different isomers.
Geometrical Isomerism:
Geometrical isomerism occurs when there is a difference in the spatial arrangement of ligands around the metal center. In this case, the complex A can exist in two forms: cis and trans.
- In the cis form, the chloride and bromide ions are adjacent to each other, while in the trans form, they are opposite to each other.
Reaction with AgNO3:
When complex A reacts with AgNO3, it forms a white precipitate. This precipitate is readily soluble in dilute aqueous ammonia.
- The formation of a white precipitate indicates the presence of chloride ions, which react with Ag+ to form AgCl.
- The solubility of the precipitate in dilute aqueous ammonia suggests the formation of a soluble complex, [Ag(NH3)2]+, which complexes with ammonia ligands.
Reaction with Cone. Ammonia:
When complex B reacts with cone. ammonia, it forms a pale yellow precipitate. This precipitate is soluble in cone. ammonia.
- The formation of a pale yellow precipitate suggests the presence of bromide ions, which react with Ag+ to form AgBr.
- The solubility of the precipitate in cone. ammonia suggests the formation of a soluble complex, [Ag(NH3)2]+, which complexes with ammonia ligands.
Conclusion:
Complex A shows both ionization isomerism and geometrical isomerism. The two isomers can be represented as [Cr(NH3)4CI]+[Br]- and [Cr(NH3)4Br]+[CI]-, with the chloride and bromide ions exchanging places. Additionally, the complex A reacts with AgNO3 to form a white precipitate soluble in dilute aqueous ammonia, indicating the presence of chloride ions. On the other hand, complex B reacts with cone. ammonia to form a pale yellow precipitate soluble in cone. ammonia, indicating the presence of bromide ions. Therefore, the isomerism shown by complex A is both ionization and geometrical isomerism.
The complex A, Cr(NH3)4CI2Br, shows both ionization isomerism and geometrical isomerism.
Ionization Isomerism:
Ionization isomerism occurs when there is a difference in the way ligands are bonded to the metal center. In this case, Cr(NH3)4CI2Br can be written as [Cr(NH3)4CI]+[Br]- or [Cr(NH3)4Br]+[CI]-. The chloride and bromide ions can exchange places with each other, resulting in two different isomers.
Geometrical Isomerism:
Geometrical isomerism occurs when there is a difference in the spatial arrangement of ligands around the metal center. In this case, the complex A can exist in two forms: cis and trans.
- In the cis form, the chloride and bromide ions are adjacent to each other, while in the trans form, they are opposite to each other.
Reaction with AgNO3:
When complex A reacts with AgNO3, it forms a white precipitate. This precipitate is readily soluble in dilute aqueous ammonia.
- The formation of a white precipitate indicates the presence of chloride ions, which react with Ag+ to form AgCl.
- The solubility of the precipitate in dilute aqueous ammonia suggests the formation of a soluble complex, [Ag(NH3)2]+, which complexes with ammonia ligands.
Reaction with Cone. Ammonia:
When complex B reacts with cone. ammonia, it forms a pale yellow precipitate. This precipitate is soluble in cone. ammonia.
- The formation of a pale yellow precipitate suggests the presence of bromide ions, which react with Ag+ to form AgBr.
- The solubility of the precipitate in cone. ammonia suggests the formation of a soluble complex, [Ag(NH3)2]+, which complexes with ammonia ligands.
Conclusion:
Complex A shows both ionization isomerism and geometrical isomerism. The two isomers can be represented as [Cr(NH3)4CI]+[Br]- and [Cr(NH3)4Br]+[CI]-, with the chloride and bromide ions exchanging places. Additionally, the complex A reacts with AgNO3 to form a white precipitate soluble in dilute aqueous ammonia, indicating the presence of chloride ions. On the other hand, complex B reacts with cone. ammonia to form a pale yellow precipitate soluble in cone. ammonia, indicating the presence of bromide ions. Therefore, the isomerism shown by complex A is both ionization and geometrical isomerism.
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A metal complex having the composition Cr(NH3)4CI2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in cone, ammonia.Q.The isomerism shown by complex A isa)ionisationb)geometricalc)linkaged)Both (a) and (b)Correct answer is option 'D'. Can you explain this answer?
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A metal complex having the composition Cr(NH3)4CI2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in cone, ammonia.Q.The isomerism shown by complex A isa)ionisationb)geometricalc)linkaged)Both (a) and (b)Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A metal complex having the composition Cr(NH3)4CI2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in cone, ammonia.Q.The isomerism shown by complex A isa)ionisationb)geometricalc)linkaged)Both (a) and (b)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metal complex having the composition Cr(NH3)4CI2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in cone, ammonia.Q.The isomerism shown by complex A isa)ionisationb)geometricalc)linkaged)Both (a) and (b)Correct answer is option 'D'. Can you explain this answer?.
A metal complex having the composition Cr(NH3)4CI2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in cone, ammonia.Q.The isomerism shown by complex A isa)ionisationb)geometricalc)linkaged)Both (a) and (b)Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A metal complex having the composition Cr(NH3)4CI2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in cone, ammonia.Q.The isomerism shown by complex A isa)ionisationb)geometricalc)linkaged)Both (a) and (b)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metal complex having the composition Cr(NH3)4CI2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in cone, ammonia.Q.The isomerism shown by complex A isa)ionisationb)geometricalc)linkaged)Both (a) and (b)Correct answer is option 'D'. Can you explain this answer?.
Solutions for A metal complex having the composition Cr(NH3)4CI2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in cone, ammonia.Q.The isomerism shown by complex A isa)ionisationb)geometricalc)linkaged)Both (a) and (b)Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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A metal complex having the composition Cr(NH3)4CI2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in cone, ammonia.Q.The isomerism shown by complex A isa)ionisationb)geometricalc)linkaged)Both (a) and (b)Correct answer is option 'D'. Can you explain this answer?, a detailed solution for A metal complex having the composition Cr(NH3)4CI2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in cone, ammonia.Q.The isomerism shown by complex A isa)ionisationb)geometricalc)linkaged)Both (a) and (b)Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of A metal complex having the composition Cr(NH3)4CI2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in cone, ammonia.Q.The isomerism shown by complex A isa)ionisationb)geometricalc)linkaged)Both (a) and (b)Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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