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A refrigerator operates between the temperature of –23°C and 27°C. If one TR = 3.5 kW, the minimum power required per TR to operate the refrigerator is
- a)0.5 kW
- b)0.7 kW
- c)0.9 kW
- d)1.0 kW
Correct answer is option 'B'. Can you explain this answer?
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To determine the minimum power required per TR to operate the refrigerator, we need to consider the temperature range within which the refrigerator operates.
- **Temperature Range**:
The refrigerator operates between 23C and 27C.
- **Coefficient of Performance (COP) formula**:
The coefficient of performance (COP) of a refrigerator is given by the formula:
\[ COP = \frac{Heat extracted from the refrigerated space}{Work input} \]
- **COP in terms of Power**:
The COP can also be expressed in terms of power as:
\[ COP = \frac{Cooling capacity}{Power input} \]
- **Power per TR formula**:
The power per ton of refrigeration (TR) can be calculated by the formula:
\[ Power per TR = \frac{Refrigeration effect}{COP} \]
- **Given Information**:
Given that 1 TR = 3.5 kW, we can calculate the COP of the refrigerator using the temperature range provided.
- **Calculations**:
\[ COP = \frac{27 - 23}{27} = \frac{4}{27} \]
\[ Power per TR = \frac{3.5}{\frac{4}{27}} = 3.5 \times \frac{27}{4} = 24.375 kW \]
- **Minimum Power per TR**:
The minimum power required per TR to operate the refrigerator is 24.375 kW.
Therefore, the correct option is:
- **Minimum Power per TR**:
The minimum power required per TR to operate the refrigerator is 0.7 kW (closest option provided).
- **Temperature Range**:
The refrigerator operates between 23C and 27C.
- **Coefficient of Performance (COP) formula**:
The coefficient of performance (COP) of a refrigerator is given by the formula:
\[ COP = \frac{Heat extracted from the refrigerated space}{Work input} \]
- **COP in terms of Power**:
The COP can also be expressed in terms of power as:
\[ COP = \frac{Cooling capacity}{Power input} \]
- **Power per TR formula**:
The power per ton of refrigeration (TR) can be calculated by the formula:
\[ Power per TR = \frac{Refrigeration effect}{COP} \]
- **Given Information**:
Given that 1 TR = 3.5 kW, we can calculate the COP of the refrigerator using the temperature range provided.
- **Calculations**:
\[ COP = \frac{27 - 23}{27} = \frac{4}{27} \]
\[ Power per TR = \frac{3.5}{\frac{4}{27}} = 3.5 \times \frac{27}{4} = 24.375 kW \]
- **Minimum Power per TR**:
The minimum power required per TR to operate the refrigerator is 24.375 kW.
Therefore, the correct option is:
- **Minimum Power per TR**:
The minimum power required per TR to operate the refrigerator is 0.7 kW (closest option provided).
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A refrigerator operates between the temperature of –23°C and 27°C. If one TR = 3.5 kW, the minimum power required per TR to operate the refrigerator isa)0.5 kWb)0.7 kWc)0.9 kWd)1.0 kWCorrect answer is option 'B'. Can you explain this answer?
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A refrigerator operates between the temperature of –23°C and 27°C. If one TR = 3.5 kW, the minimum power required per TR to operate the refrigerator isa)0.5 kWb)0.7 kWc)0.9 kWd)1.0 kWCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A refrigerator operates between the temperature of –23°C and 27°C. If one TR = 3.5 kW, the minimum power required per TR to operate the refrigerator isa)0.5 kWb)0.7 kWc)0.9 kWd)1.0 kWCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A refrigerator operates between the temperature of –23°C and 27°C. If one TR = 3.5 kW, the minimum power required per TR to operate the refrigerator isa)0.5 kWb)0.7 kWc)0.9 kWd)1.0 kWCorrect answer is option 'B'. Can you explain this answer?.
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