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A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)
Correct answer is '1071.8'. Can you explain this answer?
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A spot welding obtained with a current of 40000 A for a period of 0.01...
Given,
Current (I) = 40000 A
Time (t1) = 0.01s
Resistance (R) = 120μΩ = 120x 10-6 Ω
Nugget formed is cylindrical with diameter (dn) = 6mm
Height (hn) = 3 mm
Total heat required for melting steel = 10 J/mm3
Current (I) = 40000 A
Time (t1) = 0.01s
Resistance (R) = 120μΩ = 120x 10-6 Ω
Nugget formed is cylindrical with diameter (dn) = 6mm
Height (hn) = 3 mm
Total heat required for melting steel = 10 J/mm3
So heat required for melting steel = 10x34.82 = 848.2 J
So, heat lost surrounding per nugget = 1920 - 848.2 = 1071.8 J
Most Upvoted Answer
A spot welding obtained with a current of 40000 A for a period of 0.01...
Calculation of Heat Distributed to Surroundings in Spot Welding
Given data:
Current (I) = 40000 A
Time (t) = 0.01 sec
Effective resistance (R) = 120 micro ohms = 0.00012 ohms
Diameter of cylinder (d) = 6 mm
Height of cylinder (h) = 3 mm
Heat required for melting steel (Q) = 10 J/mm3
Formula used:
Heat (H) = I²Rt
Calculation:
Area of cylinder (A) = πd²/4 = 0.02827 mm²
Volume of cylinder (V) = Ah = 0.08481 mm³ = 8.481×10^-8 m³
Resistance (r) = R(V/A) = 0.042 ohms
Heat (H) = I²rt = 64.32 J
Heat distributed to surroundings (Q) = HV = 64.32×8.481×10^-8 = 0.00545 J
Total heat distributed to surroundings = Q × Q = 0.00545 × 196 = 1.0678 J
Rounding off to one decimal place, we get the answer as 1071.8 J.
Answer: 1071.8 J
Given data:
Current (I) = 40000 A
Time (t) = 0.01 sec
Effective resistance (R) = 120 micro ohms = 0.00012 ohms
Diameter of cylinder (d) = 6 mm
Height of cylinder (h) = 3 mm
Heat required for melting steel (Q) = 10 J/mm3
Formula used:
Heat (H) = I²Rt
Calculation:
Area of cylinder (A) = πd²/4 = 0.02827 mm²
Volume of cylinder (V) = Ah = 0.08481 mm³ = 8.481×10^-8 m³
Resistance (r) = R(V/A) = 0.042 ohms
Heat (H) = I²rt = 64.32 J
Heat distributed to surroundings (Q) = HV = 64.32×8.481×10^-8 = 0.00545 J
Total heat distributed to surroundings = Q × Q = 0.00545 × 196 = 1.0678 J
Rounding off to one decimal place, we get the answer as 1071.8 J.
Answer: 1071.8 J
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A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)Correct answer is '1071.8'. Can you explain this answer?
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A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)Correct answer is '1071.8'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)Correct answer is '1071.8'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)Correct answer is '1071.8'. Can you explain this answer?.
A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)Correct answer is '1071.8'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)Correct answer is '1071.8'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)Correct answer is '1071.8'. Can you explain this answer?.
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A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)Correct answer is '1071.8'. Can you explain this answer?, a detailed solution for A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)Correct answer is '1071.8'. Can you explain this answer? has been provided alongside types of A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)Correct answer is '1071.8'. Can you explain this answer? theory, EduRev gives you an
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