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A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3
    Correct answer is '1071.8'. Can you explain this answer?
    Verified Answer
    A spot welding obtained with a current of 40000 A for a period of 0.01...
    Given,
    Current (I) = 40000 A
    Time (t1) = 0.01s
    Resistance (R) = 120μΩ = 120x 10-6 Ω
    Nugget formed is cylindrical with diameter (dn) = 6mm
    Height (hn) = 3 mm
    Total heat required for melting steel = 10 J/mm3


    So heat required for melting steel = 10x34.82 = 848.2 J
    So, heat lost surrounding per nugget = 1920 - 848.2 = 1071.8 J
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    Most Upvoted Answer
    A spot welding obtained with a current of 40000 A for a period of 0.01...
    Calculation of Heat Distributed to Surroundings in Spot Welding

    Given data:
    Current (I) = 40000 A
    Time (t) = 0.01 sec
    Effective resistance (R) = 120 micro ohms = 0.00012 ohms
    Diameter of cylinder (d) = 6 mm
    Height of cylinder (h) = 3 mm
    Heat required for melting steel (Q) = 10 J/mm3

    Formula used:
    Heat (H) = I²Rt

    Calculation:
    Area of cylinder (A) = πd²/4 = 0.02827 mm²
    Volume of cylinder (V) = Ah = 0.08481 mm³ = 8.481×10^-8 m³
    Resistance (r) = R(V/A) = 0.042 ohms
    Heat (H) = I²rt = 64.32 J
    Heat distributed to surroundings (Q) = HV = 64.32×8.481×10^-8 = 0.00545 J
    Total heat distributed to surroundings = Q × Q = 0.00545 × 196 = 1.0678 J
    Rounding off to one decimal place, we get the answer as 1071.8 J.

    Answer: 1071.8 J
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    A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)Correct answer is '1071.8'. Can you explain this answer?
    Question Description
    A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)Correct answer is '1071.8'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)Correct answer is '1071.8'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spot welding obtained with a current of 40000 A for a period of 0.01 sec. If the effective resistance of the joint be taken as 120 micro ohms, and if the joint can be considered as a cylinder of 6mm diameter and 3 mm in height, the heat distributed to the surroundings is ________ J. (Take heat re q u ired for m eltin g steel as 10 J/mm3)Correct answer is '1071.8'. Can you explain this answer?.
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