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If A and B are symmetric matrices of same order and X=AB BA and Y=AB-BA, then transpose of XY is equal to : A) XY b) YX C) -YX Answer is C. Can you explain this?
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If A and B are symmetric matrices of same order and X=AB BA and Y=AB-B...
Solution:

Given,
A and B are symmetric matrices of same order
X=AB BA and Y=AB-BA

To find: (XY)T

Approach:

We know that (AB)T = BTAT and (BA)T = ATBT
Using this property, we can find the transpose of X.

Then, we can find the transpose of XY by using the property (XY)T = YTX

Steps:

1. Transpose of X:
(X)T = (AB-BA)T
= (AB)T - (BA)T
= BTA - ATB
(using property (AB)T = BTAT and (BA)T = ATBT)

2. XY:
XY = (AB-BA)(AB+BA)
= ABBAB - ABBBA - BABA + BABBA
= ABBAB - ABBBA - BABA + ABABB
= A(BB-BA)B - B(AB-BA)A
= A(B-B)AB - B(A-A)BA
= 0

3. Transpose of XY:
(XY)T = 0T = 0

4. Comparison:
Comparing (XY)T with options,
A) XY ≠ (XY)T
B) XY ≠ (XY)T
C) -YX = (XY)T

Therefore, the answer is C.
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If A and B are symmetric matrices of same order and X=AB BA and Y=AB-BA, then transpose of XY is equal to : A) XY b) YX C) -YX Answer is C. Can you explain this?
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