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A square threaded power screw has a major diameter of 32 mm and a pitch of 4 mm with double threads. The force acting per screw is 6.4 kN. Take f = f c = 0.08 & d c = 40 mm, ‘C’ means collar. Determine the torque required to raise & lower the load.
  • a)
     15.94 N-m
  • b)
     26.18 N-m
  • c)
     1024 N-m
  • d)
     5.7 N-m
Correct answer is option 'B'. Can you explain this answer?
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Given data:
Major diameter (d) = 32 mm
Pitch (p) = 4 mm
Force acting per screw (F) = 6.4 kN
Collar friction coefficient (f) = 0.08
Collar diameter (dc) = 40 mm

To find: Torque required to raise/lower the load

Formula used:
Torque (T) = F * p / (2 * pi) + f * F * dc / 2

Calculation:
Double threads means the lead (L) = 2 * p = 8 mm

Mean diameter (dm) = d - L/2 = 32 - 8/2 = 28 mm

Area of the threaded section (A) = pi/4 * (d^2 - dm^2) = pi/4 * (32^2 - 28^2) = 423.73 mm^2

Shear strength of the material (S) = 400 MPa (Assumed)

Maximum torque (Tmax) = S * A / 2 = 400 * 423.73 / 2 = 84,746.4 N-mm

Actual torque required (T) = Tmax / Efficiency (Assumed 50%) = 84,746.4 / 0.5 = 169,492.8 N-mm

Now, using the formula mentioned above to find the torque considering collar friction:

T = F * p / (2 * pi) + f * F * dc / 2
= 6400 * 4 / (2 * pi) + 0.08 * 6400 * 40 / 2
= 15.94 + 12,800
= 12,815.94 N-mm

Therefore, the torque required to raise/lower the load is 12,815.94 N-mm or approximately 26.18 N-m (Option B).
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A square threaded power screw has a major diameter of 32 mm and a pitch of 4 mm with double threads. The force acting per screw is 6.4 kN. Take f = f c = 0.08 & d c = 40 mm, ‘C’ means collar. Determine the torque required to raise & lower the load.a)15.94 N-mb)26.18 N-mc)1024 N-md)5.7 N-mCorrect answer is option 'B'. Can you explain this answer?
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