**Distance Covered by a Body Projected Vertically Upwards**

When a body is projected vertically upwards, it follows a parabolic trajectory due to the force of gravity acting on it. The distance covered by the body during its upward journey is equal to the distance covered during its downward journey. In order to calculate the total distance covered by the body, we need to consider both the upward and downward journeys.

Let's assume the initial velocity of the body when it is projected upwards is 'u', the total distance covered by the body is 'D', and the time of flight is 't'.

**1. Distance Covered during the Upward Journey:**

During the upward journey, the body moves against the force of gravity. The formula to calculate the distance covered during the upward journey is given by:

\[S_{up} = ut - \frac{1}{2}gt^2\]

where:
- \(S_{up}\) is the distance covered during the upward journey.
- 'u' is the initial velocity of the body.
- 'g' is the acceleration due to gravity, which is approximately 9.8 m/s².
- 't' is the time of flight.

**2. Distance Covered during the Downward Journey:**

During the downward journey, the body moves along with the force of gravity. The formula to calculate the distance covered during the downward journey is given by:

\[S_{down} = \frac{1}{2}gt^2\]

where:
- \(S_{down}\) is the distance covered during the downward journey.
- 'g' is the acceleration due to gravity.
- 't' is the time of flight.

**3. Total Distance Covered by the Body:**

The total distance covered by the body is the sum of the distances covered during the upward and downward journeys:

\[D = S_{up} + S_{down} = (ut - \frac{1}{2}gt^2) + (\frac{1}{2}gt^2)\]

Simplifying the equation, we get:

\[D = ut\]

So, the total distance covered by the body is equal to the product of its initial velocity and the time of flight.

**4. Distance Covered in the Absence of Gravity:**

If there were no gravity, the body would continue moving with a constant velocity in the upward direction. The distance covered by the body during the same time 't' would be equal to:

\[S_{no gravity} = ut\]

In the absence of gravity, the body would cover the same distance as it would in the presence of gravity.

Therefore, the distance covered by a body when projected vertically upwards during the same time 't' in the absence of gravity is equal to the product of its initial velocity and the time of flight, which is the same as the total distance covered in the presence of gravity.

4D?