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The resistance of a wire of length / and area of cross-section a is x ohm. If the wire is stretched to double its length, its resistance would become:
  • a)
    2x ohm
  • b)
    0.5 x ohm
  • c)
    4x ohm
  • d)
    6x ohm
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The resistance of a wire of length / and area of cross-section a is x ...
Resistance is directly proportional to length(l)
r ∝ 1 5 r ∝ 1/a
wire is stretched to double its length the resistance will become
r ∝ 1, r ∝ 1/a/2 Combining these two r ∝ 41/a 
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Most Upvoted Answer
The resistance of a wire of length / and area of cross-section a is x ...
Resistance of a Wire

The resistance of a wire is determined by its length, cross-sectional area, and the material it is made of. According to Ohm's law, the resistance (R) of a wire is given by the formula R = ρ * (L / A), where ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area.

Given Information

In the given question, we are told that the resistance of a wire of length L and cross-sectional area A is x ohms. Let's denote this as R1 = x ohms.

Effect of Stretching the Wire

When the wire is stretched to double its length, its new length becomes 2L. We need to find the new resistance of the wire, which we'll denote as R2.

Using Ohm's Law

Let's use Ohm's law to find the new resistance of the wire.

R2 = ρ * (2L / A)

Since the resistivity and cross-sectional area of the wire remain the same, we can simplify the equation as follows:

R2 = 2 * ρ * (L / A)

Comparing R2 and R1

We know that R1 = x ohms, so we can compare R2 and R1 to determine the relationship between them.

R2 / R1 = (2 * ρ * (L / A)) / x

Simplifying further:

R2 / R1 = 2 * (L / A) * (ρ / x)

Since (L / A) and (ρ / x) are constant values for the wire, we can write:

R2 / R1 = constant

This means that the ratio of R2 to R1 remains constant. Therefore, the new resistance of the wire (R2) is directly proportional to the initial resistance (R1).

Conclusion

Since the initial resistance (R1) is x ohms, the new resistance (R2) will be 2x ohms when the wire is stretched to double its length.

Therefore, the correct answer is option C) 4x ohms.
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The resistance of a wire of length / and area of cross-section a is x ohm. If the wire is stretched to double its length, its resistance would become:a)2x ohmb)0.5 x ohmc)4x ohmd)6x ohmCorrect answer is option 'C'. Can you explain this answer?
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