The resistance of a wire of length / and area of cross-section a is x ...
Resistance is directly proportional to length(l)
r ∝ 1 5 r ∝ 1/a
wire is stretched to double its length the resistance will become
r ∝ 1, r ∝ 1/a/2 Combining these two r ∝ 41/a
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The resistance of a wire of length / and area of cross-section a is x ...
Resistance of a Wire
The resistance of a wire is determined by its length, cross-sectional area, and the material it is made of. According to Ohm's law, the resistance (R) of a wire is given by the formula R = ρ * (L / A), where ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area.
Given Information
In the given question, we are told that the resistance of a wire of length L and cross-sectional area A is x ohms. Let's denote this as R1 = x ohms.
Effect of Stretching the Wire
When the wire is stretched to double its length, its new length becomes 2L. We need to find the new resistance of the wire, which we'll denote as R2.
Using Ohm's Law
Let's use Ohm's law to find the new resistance of the wire.
R2 = ρ * (2L / A)
Since the resistivity and cross-sectional area of the wire remain the same, we can simplify the equation as follows:
R2 = 2 * ρ * (L / A)
Comparing R2 and R1
We know that R1 = x ohms, so we can compare R2 and R1 to determine the relationship between them.
R2 / R1 = (2 * ρ * (L / A)) / x
Simplifying further:
R2 / R1 = 2 * (L / A) * (ρ / x)
Since (L / A) and (ρ / x) are constant values for the wire, we can write:
R2 / R1 = constant
This means that the ratio of R2 to R1 remains constant. Therefore, the new resistance of the wire (R2) is directly proportional to the initial resistance (R1).
Conclusion
Since the initial resistance (R1) is x ohms, the new resistance (R2) will be 2x ohms when the wire is stretched to double its length.
Therefore, the correct answer is option C) 4x ohms.