Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > A 400-V, 1000-A, lap wound dc machine has 10 ... Start Learning for Free
A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature conductors. The number of conductors in the pole face to give full compensation if pole face covers 70% of pole span is
- a)3010
- b)4300
- c)2400
- d)2800
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature condu...
AT/pole for the compensating winding = 0.7*(Z*I/2P)
= 0.7*(860*100/2*10)
= 3010 AT.
= 0.7*(860*100/2*10)
= 3010 AT.
Most Upvoted Answer
A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature condu...
To determine the number of conductors in the pole face that will provide full compensation, we need to use the following formula:
Number of conductors in pole face = (Pole span / Pitch factor) - 1
Where:
- Pole span: The angular distance between the center of two adjacent poles.
- Pitch factor: The fraction of the pole pitch covered by the pole face.
Given data:
- Voltage (V) = 400 V
- Current (I) = 1000 A
- Number of poles (P) = 10
- Number of armature conductors (N) = 860
First, we need to calculate the pole pitch (Y):
Pole pitch (Y) = (N / P) = (860 / 10) = 86
Next, we can calculate the pole span (Z):
Pole span (Z) = 360° / P = 360° / 10 = 36°
Now, we can determine the pitch factor (K):
Pitch factor (K) = Pole face coverage / Pole span = 0.7
Substituting the values into the formula:
Number of conductors in pole face = (36° / 0.7) - 1 = 51.43 - 1 = 50.43
Since the number of conductors must be an integer value, we round up to the nearest whole number:
Number of conductors in pole face = 51
Finally, we can calculate the total number of conductors in the pole face:
Total number of conductors in pole face = Number of conductors in pole face * P = 51 * 10 = 510
Therefore, the correct answer is option A) 3010 conductors.
Number of conductors in pole face = (Pole span / Pitch factor) - 1
Where:
- Pole span: The angular distance between the center of two adjacent poles.
- Pitch factor: The fraction of the pole pitch covered by the pole face.
Given data:
- Voltage (V) = 400 V
- Current (I) = 1000 A
- Number of poles (P) = 10
- Number of armature conductors (N) = 860
First, we need to calculate the pole pitch (Y):
Pole pitch (Y) = (N / P) = (860 / 10) = 86
Next, we can calculate the pole span (Z):
Pole span (Z) = 360° / P = 360° / 10 = 36°
Now, we can determine the pitch factor (K):
Pitch factor (K) = Pole face coverage / Pole span = 0.7
Substituting the values into the formula:
Number of conductors in pole face = (36° / 0.7) - 1 = 51.43 - 1 = 50.43
Since the number of conductors must be an integer value, we round up to the nearest whole number:
Number of conductors in pole face = 51
Finally, we can calculate the total number of conductors in the pole face:
Total number of conductors in pole face = Number of conductors in pole face * P = 51 * 10 = 510
Therefore, the correct answer is option A) 3010 conductors.
 | Explore Courses for Electrical Engineering (EE) exam |  |
Top Courses for Electrical Engineering (EE)View all
Top Courses for Electrical Engineering (EE)
Question Description
A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature conductors. The number of conductors in the pole face to give full compensation if pole face covers 70% of pole span isa)3010b)4300c)2400d)2800Correct answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature conductors. The number of conductors in the pole face to give full compensation if pole face covers 70% of pole span isa)3010b)4300c)2400d)2800Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature conductors. The number of conductors in the pole face to give full compensation if pole face covers 70% of pole span isa)3010b)4300c)2400d)2800Correct answer is option 'A'. Can you explain this answer?.
A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature conductors. The number of conductors in the pole face to give full compensation if pole face covers 70% of pole span isa)3010b)4300c)2400d)2800Correct answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature conductors. The number of conductors in the pole face to give full compensation if pole face covers 70% of pole span isa)3010b)4300c)2400d)2800Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature conductors. The number of conductors in the pole face to give full compensation if pole face covers 70% of pole span isa)3010b)4300c)2400d)2800Correct answer is option 'A'. Can you explain this answer?.
Solutions for A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature conductors. The number of conductors in the pole face to give full compensation if pole face covers 70% of pole span isa)3010b)4300c)2400d)2800Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature conductors. The number of conductors in the pole face to give full compensation if pole face covers 70% of pole span isa)3010b)4300c)2400d)2800Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature conductors. The number of conductors in the pole face to give full compensation if pole face covers 70% of pole span isa)3010b)4300c)2400d)2800Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature conductors. The number of conductors in the pole face to give full compensation if pole face covers 70% of pole span isa)3010b)4300c)2400d)2800Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature conductors. The number of conductors in the pole face to give full compensation if pole face covers 70% of pole span isa)3010b)4300c)2400d)2800Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A 400-V, 1000-A, lap wound dc machine has 10 poles, 860 armature conductors. The number of conductors in the pole face to give full compensation if pole face covers 70% of pole span isa)3010b)4300c)2400d)2800Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
| Explore Courses for Electrical Engineering (EE) exam | |
Top Courses for Electrical Engineering (EE)
Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
