Two straight lines passing through the point A(3,2) cut the line 2y = ...
Coordinates of Q are (3,0) & it passes through PQ.
Putting the values of(x=3) & (y=0) m options we get:
Equation of line PQ = 7x + y - 21 = 0
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Two straight lines passing through the point A(3,2) cut the line 2y = ...
Given Information:
- Point A(3,2)
- Line 2y = x - 3
- Perpendicular lines passing through A(3,2) cutting the given line and x-axis at points P and Q
Solution:
Finding the Slope of the Given Line:
- The given line is in the form 2y = x - 3, which can be rewritten as y = (1/2)x - 3/2
- The slope of this line is 1/2
Finding the Slope of the Perpendicular Lines:
- The product of slopes for perpendicular lines is -1
- So, the slope of the perpendicular lines passing through A(3,2) will be -2
Equation of Line Passing Through A(3,2) with Slope -2:
- Using the point-slope form of the line equation: y - y₁ = m(x - x₁), where (x₁, y₁) = (3,2) and m = -2
- y - 2 = -2(x - 3)
- y - 2 = -2x + 6
- 2x + y - 8 = 0
Equation of Line PQ:
- Since P lies on the given line 2y = x - 3 and Q lies on the x-axis (y = 0), we can find the coordinates of P and Q
- Substitute y = 0 in 2y = x - 3 to find Q: x = 3
- So, Q(3,0) and P satisfies the equation 2x + y - 8 = 0: 2(3) + 0 - 8 = 6 - 8 = -2
- So, P(3,-2)
- Therefore, the equation of line PQ passing through P and Q is 2x + y - 8 = 0
Therefore, the correct answer is option 'A'.